To solve these questions, let’s analyze the equations:

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Equation A: $y = 3x + 5$

This is in the slope-intercept form $y = mx + b$, where:

• $m$ is the slope.
• $b$ is the y-intercept.

From $y = 3x + 5$:

• Slope: $m = 3$
• y-intercept: $b = 5$

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Equation B: $y = 3x$

This is also in the slope-intercept form $y = mx + b$.

From $y = 3x$:

• Slope: $m = 3$
• y-intercept: $b = 0$ (since there is no constant term, the y-intercept is 0).

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Final Answers:

1. For Equation A:

   • Slope = $3$
   • y-intercept = $5$

2. For Equation B:

   • Slope = $3$
   • y-intercept = $0$

Would you like detailed explanations on finding slopes and intercepts?

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Related Questions:

1. How would the graph of $y = 3x + 5$ differ from $y = 3x$?
2. If $y = 3x + 5$, what is the value of $y$ when $x = -2$?
3. How does the slope affect the steepness of the lines in both equations?
4. What are the points of intersection between the two lines $y = 3x + 5$ and $y = 3x$?
5. How would the equations change if the slopes were doubled?

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Tip:

The slope determines the steepness and direction of a line, while the y-intercept determines where the line crosses the y-axis.