Math Problem Statement

lim G(x), given G(x) = |2x - 3| - 4 as x approaches to 3/2

Solution

To find the limit of G(x)=2x34G(x) = |2x - 3| - 4 as xx approaches 32\frac{3}{2}, we can follow these steps:

  1. Substitute x=32x = \frac{3}{2} directly into the expression:

    G(32)=2(32)34G\left(\frac{3}{2}\right) = \left|2\left(\frac{3}{2}\right) - 3\right| - 4

  2. Simplify inside the absolute value:

    G(32)=334=04=04=4G\left(\frac{3}{2}\right) = \left|3 - 3\right| - 4 = |0| - 4 = 0 - 4 = -4

  3. Evaluate the limit:

    Since the function G(x)=2x34G(x) = |2x - 3| - 4 is continuous at x=32x = \frac{3}{2}, the limit as xx approaches 32\frac{3}{2} is simply the value of the function at that point.

    limx32G(x)=G(32)=4\lim_{{x \to \frac{3}{2}}} G(x) = G\left(\frac{3}{2}\right) = -4

So, the limit is:

limx32G(x)=4\lim_{{x \to \frac{3}{2}}} G(x) = -4

Would you like more details, or do you have any other questions?

Here are some related questions to further explore this topic:

  1. What is the derivative of G(x)=2x34G(x) = |2x - 3| - 4 with respect to xx?
  2. How would the limit change if G(x)=2x34G(x) = |2x - 3| - 4 was evaluated as xx approaches a different value?
  3. Can you explain the concept of continuity and how it relates to evaluating limits?
  4. How would you graph G(x)=2x34G(x) = |2x - 3| - 4 and interpret the result?
  5. What happens to the limit of G(x)=2x34G(x) = |2x - 3| - 4 as xx approaches infinity?

Tip: When evaluating limits involving absolute values, consider the points where the expression inside the absolute value changes sign, as these are critical points to analyze the behavior of the function.

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Math Problem Analysis

Mathematical Concepts

Limits
Absolute Value Functions

Formulas

-

Theorems

Limit properties
Continuity

Suitable Grade Level

Advanced High School