Math Problem Statement
Solution
We are asked to compute the limit of the vector as .
Let's break this down component-wise:
1. :
- The arctangent function, , has a horizontal asymptote at as approaches infinity.
- Therefore,
2. :
- The exponential function decays to zero as approaches infinity since becomes smaller and smaller.
- Therefore,
3. :
- This is a logarithmic function divided by a linear term. We can use L'Hopital's Rule because this is an indeterminate form of type .
- Differentiate the numerator and denominator:
- The derivative of is ,
- The derivative of is .
- Applying L'Hopital's Rule:
Final Answer:
The limit of the vector is
Would you like any further details or clarification on any part?
Here are some related questions you might find helpful:
- How does L'Hopital's Rule work, and when can it be applied?
- What is the behavior of exponential functions as ?
- Can arctangent functions have asymptotes?
- How do logarithmic functions behave compared to linear and polynomial functions at infinity?
- What are the common indeterminate forms that can occur in limits?
Tip: When evaluating limits of logarithmic and polynomial functions, comparing growth rates (like using L'Hopital's Rule) is very useful.
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Math Problem Analysis
Mathematical Concepts
Limits
Logarithmic Functions
Exponential Decay
Trigonometric Limits
Formulas
lim t → ∞ arctan(t) = π/2
lim t → ∞ e^(-3t) = 0
lim t → ∞ ln(6t)/t = 0
Theorems
L'Hopital's Rule
Limit of Exponential Functions at Infinity
Trigonometric Limit (arctangent function)
Suitable Grade Level
Undergraduate Level
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