Math Problem Statement

Solve using T-Table and Graph

Evaluate the limit using all three methods/approaches: Analytical, Numerical (T-Table), and Graphical for the given expression lim(x -> 0) (|x+2| - 2) / |x|.

Solution

Numerical Approach (T-Table)

Here is the T-Table showing the values of f(x)=x+22xf(x) = \frac{|x+2| - 2}{|x|} for values of xx approaching 0:

xxf(x)f(x)
-0.100-1.0
-0.010-1.0
-0.001-1.0
0.0011.0
0.0101.0
0.1001.0
  • As xx approaches 0 from the left (x0x \to 0^-), f(x)f(x) tends to -1.
  • As xx approaches 0 from the right (x0+x \to 0^+), f(x)f(x) tends to 1.

Graphical Approach

The graph of the function f(x)f(x) around x=0x = 0 shows a jump discontinuity. From the left, the function approaches -1, and from the right, it approaches 1. The graph confirms that the limit does not exist at x=0x = 0 because the left-hand limit and the right-hand limit are not equal.

Conclusion

The limit does not exist since:

limx0f(x)=1andlimx0+f(x)=1\lim_{x \to 0^-} f(x) = -1 \quad \text{and} \quad \lim_{x \to 0^+} f(x) = 1

If you need further clarification or details, feel free to ask!

Here are 5 related questions to expand your understanding:

  1. What conditions must be met for a two-sided limit to exist?
  2. How does absolute value influence the behavior of functions at critical points like 0?
  3. How can we formally prove the non-existence of a limit using epsilon-delta definitions?
  4. What are some other ways to calculate limits involving absolute value functions?
  5. How do piecewise functions relate to the concept of one-sided limits?

Tip: When dealing with absolute value in limits, it's helpful to separately evaluate limits from the left and right to understand the function's behavior.

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Math Problem Analysis

Mathematical Concepts

Limits
Absolute Value Functions
Continuity
Piecewise Functions

Formulas

lim(x -> 0) (|x+2| - 2) / |x|

Theorems

Limit Theorem
Left-Hand and Right-Hand Limits
Discontinuity Theorem

Suitable Grade Level

Grades 11-12, Early College