Math Problem Statement

Evaluate the limit: lim (x → 0) [x / |x|]

Solution

The limit provided is:

limx0xx\lim_{{x \to 0}} \frac{x}{|x|}

Solution:

We need to analyze the behavior of this expression as x0x \to 0, which requires us to break it into two cases based on the definition of the absolute value function x|x|.

  1. When x>0x > 0:

    • In this case, x=x|x| = x. xx=xx=1\frac{x}{|x|} = \frac{x}{x} = 1 Therefore, as x0+x \to 0^+ (from the right), the limit is: limx0+xx=1\lim_{{x \to 0^+}} \frac{x}{|x|} = 1
  2. When x<0x < 0:

    • In this case, x=x|x| = -x. xx=xx=1\frac{x}{|x|} = \frac{x}{-x} = -1 Therefore, as x0x \to 0^- (from the left), the limit is: limx0xx=1\lim_{{x \to 0^-}} \frac{x}{|x|} = -1

Conclusion:

The left-hand limit as x0x \to 0^- is 1-1, and the right-hand limit as x0+x \to 0^+ is 11. Since these two limits do not match, the overall limit does not exist.

So: limx0xx does not exist.\lim_{{x \to 0}} \frac{x}{|x|} \text{ does not exist}.

Would you like further details or have any questions?

Related Questions:

  1. What is the formal definition of a limit not existing at a point?
  2. How does the absolute value function impact limits in general?
  3. What happens if the function inside the limit was xx\frac{|x|}{x}?
  4. Can the limit of piecewise functions exist if one-sided limits differ?
  5. How do you compute limits approaching infinity involving absolute values?

Tip:

When working with absolute value functions, always consider breaking the analysis into cases where xx is positive and where xx is negative.

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Math Problem Analysis

Mathematical Concepts

Limits
Absolute Value
Piecewise Functions

Formulas

lim (x → 0) [x / |x|]

Theorems

Limit Theorem for One-Sided Limits

Suitable Grade Level

Grades 11-12