Math Problem Statement

Sketch the level curves of f(x, y) = x^2 + 4y^2 at levels c = 0, 1,4,9,1,6,25

Solution

The given function is f(x,y)=x2+4y2f(x, y) = x^2 + 4y^2. To sketch the level curves, we set f(x,y)=cf(x, y) = c for various values of cc. This gives us the equation for each level curve:

x2+4y2=cx^2 + 4y^2 = c

This is the equation of an ellipse centered at the origin. For each value of cc, the equation describes a different ellipse (or point, if c=0c = 0).

Step-by-step breakdown for each level:

  1. For c=0c = 0: x2+4y2=0x^2 + 4y^2 = 0 This only holds when x=0x = 0 and y=0y = 0, so the level curve is a point at the origin.

  2. For c=1c = 1: x2+4y2=1x^2 + 4y^2 = 1 Dividing by 1, we get: x21+y214=1\frac{x^2}{1} + \frac{y^2}{\frac{1}{4}} = 1 This is an ellipse with semi-major axis 1 along the xx-axis and semi-minor axis 12\frac{1}{2} along the yy-axis.

  3. For c=4c = 4: x2+4y2=4x^2 + 4y^2 = 4 Dividing by 4, we get: x24+y21=1\frac{x^2}{4} + \frac{y^2}{1} = 1 This is an ellipse with semi-major axis 2 along the xx-axis and semi-minor axis 1 along the yy-axis.

  4. For c=9c = 9: x2+4y2=9x^2 + 4y^2 = 9 Dividing by 9, we get: x29+y294=1\frac{x^2}{9} + \frac{y^2}{\frac{9}{4}} = 1 This is an ellipse with semi-major axis 3 along the xx-axis and semi-minor axis 32\frac{3}{2} along the yy-axis.

  5. For c=16c = 16: x2+4y2=16x^2 + 4y^2 = 16 Dividing by 16, we get: x216+y24=1\frac{x^2}{16} + \frac{y^2}{4} = 1 This is an ellipse with semi-major axis 4 along the xx-axis and semi-minor axis 2 along the yy-axis.

  6. For c=25c = 25: x2+4y2=25x^2 + 4y^2 = 25 Dividing by 25, we get: x225+y2254=1\frac{x^2}{25} + \frac{y^2}{\frac{25}{4}} = 1 This is an ellipse with semi-major axis 5 along the xx-axis and semi-minor axis 52\frac{5}{2} along the yy-axis.

Summary of ellipses:

  • c=0c = 0: Point at the origin.
  • c=1c = 1: Ellipse with axes 1 (x-axis) and 0.5 (y-axis).
  • c=4c = 4: Ellipse with axes 2 (x-axis) and 1 (y-axis).
  • c=9c = 9: Ellipse with axes 3 (x-axis) and 1.5 (y-axis).
  • c=16c = 16: Ellipse with axes 4 (x-axis) and 2 (y-axis).
  • c=25c = 25: Ellipse with axes 5 (x-axis) and 2.5 (y-axis).

Would you like further details, such as a visual sketch of these curves?


Here are some related questions to explore:

  1. What is the general form of an ellipse equation?
  2. How do changes in the coefficients of x2x^2 and y2y^2 affect the shape of the ellipse?
  3. How can you find the area of each ellipse given the equation f(x,y)f(x, y)?
  4. What are the differences between ellipses and circles in terms of their equations?
  5. How would the level curves change if we had x2+2y2x^2 + 2y^2 instead?

Tip: In an ellipse equation x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, aa and bb represent the lengths of the semi-major and semi-minor axes, respectively.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Level Curves
Ellipses

Formulas

f(x, y) = x^2 + 4y^2
Equation of an ellipse: (x^2 / a^2) + (y^2 / b^2) = 1

Theorems

Conic Sections
Ellipse Equation

Suitable Grade Level

Undergraduate (Calculus I/II)