Math Problem Statement

f(x,y) = xy (a) determine several level curves of the given function f using -2, -1, 0, 1, 2(make sure to indicate the height c of each curve); (b) use the information obtained in part (a) to sketch the graph of f.

Solution

Given function:

f(x,y)=xyf(x, y) = xy

(a) Determine several level curves of the given function for c=2,1,0,1,2c = -2, -1, 0, 1, 2.

The level curves of a function f(x,y)f(x, y) for a constant cc are the curves along which the function equals cc, i.e., for each cc, the equation becomes: xy=cxy = c

This equation represents a family of hyperbolas. Let's find the level curves for the given values of cc:

  1. For c=2c = -2: xy=2y=2xxy = -2 \quad \Rightarrow \quad y = \frac{-2}{x} This is a hyperbola opening in the 2nd and 4th quadrants.

  2. For c=1c = -1: xy=1y=1xxy = -1 \quad \Rightarrow \quad y = \frac{-1}{x} This is another hyperbola, but it will be closer to the origin than the one for c=2c = -2.

  3. For c=0c = 0: xy=0y=0orx=0xy = 0 \quad \Rightarrow \quad y = 0 \quad \text{or} \quad x = 0 This corresponds to the coordinate axes (the x-axis and y-axis), where the function value is zero.

  4. For c=1c = 1: xy=1y=1xxy = 1 \quad \Rightarrow \quad y = \frac{1}{x} This is a hyperbola opening in the 1st and 3rd quadrants.

  5. For c=2c = 2: xy=2y=2xxy = 2 \quad \Rightarrow \quad y = \frac{2}{x} This is another hyperbola, opening in the 1st and 3rd quadrants, but farther from the origin than the one for c=1c = 1.

Thus, the equations of the level curves are:

  • For c=2c = -2, y=2xy = \frac{-2}{x}
  • For c=1c = -1, y=1xy = \frac{-1}{x}
  • For c=0c = 0, x=0x = 0 or y=0y = 0
  • For c=1c = 1, y=1xy = \frac{1}{x}
  • For c=2c = 2, y=2xy = \frac{2}{x}

(b) Sketching the graph of f(x,y)=xyf(x, y) = xy:

  1. The graph consists of level curves that represent hyperbolas in various orientations (depending on whether the value of cc is positive or negative).
  2. The level curve for c=0c = 0 corresponds to the coordinate axes (x-axis and y-axis).
  3. The hyperbolas get closer to the origin as the magnitude of cc decreases, and they move farther from the origin as c|c| increases.

To summarize the graph of f(x,y)f(x, y):

  • For positive values of cc, the hyperbolas are in the 1st and 3rd quadrants.
  • For negative values of cc, the hyperbolas are in the 2nd and 4th quadrants.
  • The axes x=0x = 0 and y=0y = 0 correspond to the level curve c=0c = 0.

Would you like further details on how to sketch the graph step by step? Or would you like help with other functions? Here are a few related questions you might find interesting:

  1. How does the graph of a function change when the function is multiplied by a constant?
  2. What happens to the level curves if the function was f(x,y)=x2+y2f(x, y) = x^2 + y^2?
  3. How can we determine the symmetry of a function based on its level curves?
  4. What would the graph of a function f(x,y)=x+yf(x, y) = x + y look like?
  5. How does the equation xy=cxy = c behave for very large or very small values of cc?

Tip: Always visualize level curves by drawing a set of coordinate axes and sketching the curves for various cc values. It will help you understand the function’s behavior better.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Level Curves
Graphing Functions
Hyperbolas

Formulas

Level Curve Equation: xy = c

Theorems

Level Curve Interpretation
Graphical Representation of Functions

Suitable Grade Level

Undergraduate (Calculus I/II)