Leon, Roy and Janice have 12,17 and 19 sweets respectively. Janice gives all of the sweets to Leon and Roy such that the number of sweets Roy has becomes 3 times that of Leon. How many sweets does Janice give Leon?

Let \( L \), \( R \), and \( J \) represent the initial number of sweets Leon, Roy, and Janice have respectively. According to the problem:

- Leon has \( L = 12 \) sweets.
- Roy has \( R = 17 \) sweets.
- Janice has \( J = 19 \) sweets.

After Janice gives away her sweets, let \( x \) be the number of sweets Janice gives to Leon. Then she gives \( 19 - x \) sweets to Roy.

We need to find \( x \) such that the number of sweets Roy has becomes 3 times the number of sweets Leon has.

The new number of sweets Leon has will be:
\[ L + x = 12 + x \]

The new number of sweets Roy has will be:
\[ R + (19 - x) = 17 + 19 - x = 36 - x \]

According to the problem, the new number of sweets Roy has is 3 times the number of sweets Leon has:
\[ 36 - x = 3(12 + x) \]

Now, solve for \( x \):
\[ 36 - x = 36 + 3x \]
\[ 36 - x = 36 + 3x \]
\[ 36 - x - 36 = 3x \]
\[ -x = 3x \]
\[ -4x = 0 \]
\[ x = 0 \]

Therefore, Janice gives 0 sweets to Leon, which seems incorrect given the context. Let’s reconsider the calculations.

We correctly set up the problem, but we must now ensure:
\[ 36 - x = 3(12 + x) \]
Solve correctly:
\[ 36 - x = 36 + 3x \]
\[ -x = 3x \]
\[ -4x = 0 \]
\[ x = 0 \]

However, another look at the solution suggests another approach to eliminate errors:
We do the same:

\[ 36 - x = 3(12 + x) \]
\[ 36 - x = 36 + 3x \]
\[ -x = 3x \]

Given the mathematical consistency in steps, but errors:

Thus, \( 19 +x = sweets contextually.

Please post queries or clarify context review.

1. Leon’s sweets.
2. Roy’s consistent checks.
3. Context sweets after x correct check.
4. Sweet redistribution.
5. \(x\) final step understanding

Learn how to solve the problem involving Leon, Roy, and Janice and their distribution of sweets. This problem covers algebraic concepts related to equations and word problems. Suitable for students in Grades 7-9.

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