Paula, Bobby and Charlie shared a box of sweets. Bobby received twice as many sweets as Paula. Charlie received thrice as many sweets as Bobby. If Charlie received 165 more sweets than Paula, how many sweets did Charlie receive?

Let's define the variables to represent the number of sweets each person received:

- Let \( P \) represent the number of sweets Paula received.
- Bobby received twice as many sweets as Paula, so Bobby received \( 2P \) sweets.
- Charlie received thrice as many sweets as Bobby, so Charlie received \( 3 \times 2P = 6P \) sweets.

We are told that Charlie received 165 more sweets than Paula. This can be written as:
\[
6P = P + 165
\]

Now, let's solve this equation step by step:

1. Subtract \( P \) from both sides:
\[
6P - P = 165
\]
\[
5P = 165
\]

2. Divide both sides by 5:
\[
P = \frac{165}{5} = 33
\]

Now that we know Paula received 33 sweets, we can calculate how many sweets Charlie received:
\[
6P = 6 \times 33 = 198
\]

Therefore, Charlie received **198** sweets.

Would you like further explanation or details on the problem? Here are some related questions:

1. How many sweets did Bobby receive?
2. How many sweets did Paula receive?
3. What was the total number of sweets shared among Paula, Bobby, and Charlie?
4. If Charlie had received 10 more sweets, how many would he have received in total?
5. What is the ratio of sweets received by Paula, Bobby, and Charlie?

**Tip:** Always start by defining variables and building relationships based on the problem statement when solving word problems.

Solve the algebraic problem where Paula, Bobby, and Charlie share a box of sweets. Learn how Charlie, receiving thrice as many sweets as Bobby, ends up with 198 sweets, and how algebra helps in determining this. Suitable for Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation