Math Problem Statement

Use the Law of Sines to solve the triangle, if possible. Given A = 34.9°, a = 27, b = 32.

Solution

We are tasked with solving a triangle using the Law of Sines. The given values are:

  • A=34.9A = 34.9^\circ
  • a=27a = 27
  • b=32b = 32

To solve this, we'll apply the Law of Sines:

sinAa=sinBb\frac{\sin A}{a} = \frac{\sin B}{b}

We will calculate the value of angle BB, and depending on the results, check if there are one or two possible solutions. Then, we can compute angle CC using the fact that the sum of angles in a triangle is 180180^\circ and finally calculate side cc using the Law of Sines again.

Let me start calculating these values.Based on the calculations:

  • For Solution 1 (smaller angle B1B_1):

    • B1=42.7B_1 = 42.7^\circ
    • C1=102.4C_1 = 102.4^\circ
    • c1=46c_1 = 46 (rounded)
  • For Solution 2 (larger angle B2B_2):

    • B2=137.3B_2 = 137.3^\circ
    • C2=7.8C_2 = 7.8^\circ
    • c2=6.4c_2 = 6.4 (rounded)

This means there are two possible solutions for the triangle, so the correct choice is B.

Would you like further clarification or additional details?

Here are 5 related questions to explore:

  1. What happens if the sine of an angle is greater than 1?
  2. How does the Law of Sines help in solving non-right triangles?
  3. Can the Law of Sines be used in all triangles? Why or why not?
  4. How do you handle cases where there are two possible solutions for a triangle?
  5. What are some real-world applications of the Law of Sines?

Tip: Always check if the sine value is between -1 and 1 to ensure valid angle calculations when using the Law of Sines.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines
Ambiguous Case
Triangle Properties

Formulas

sin(A)/a = sin(B)/b
Sum of angles in a triangle = 180°

Theorems

Law of Sines

Suitable Grade Level

Grades 10-12