Math Problem Statement
Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that ∠B1 is larger than ∠B2.) a = 33, c = 44, ∠A = 39° ∠B1 = ° ∠B2 = ° ∠C1 = ° ∠C2 = ° b1 =
b2 =
Solution
We are given the following conditions for a triangle:
We need to solve for the two possible triangles that satisfy these conditions using the Law of Sines.
Step 1: Use the Law of Sines
The Law of Sines states that:
From the information provided, we can first calculate the value of :
Now, we can use this to find angle (there are two possible cases for ).
Step 2: Solve for
Using the Law of Sines:
This simplifies to:
Now, solving for :
Since the sum of angles in a triangle is 180°, we can calculate :
For the second possible angle , we use the fact that , which gives us the second solution for :
Now, calculating :
Step 3: Solve for sides and
Now, using the Law of Sines again to find the lengths of side for each case.
For and :
For and :
Final Answers
Tip:
When applying the Law of Sines, always check if the given conditions can create two possible solutions for the triangle, especially when an angle has two possible corresponding values.
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Law of Sines
Triangle Properties
Formulas
Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)
Theorems
Law of Sines
Suitable Grade Level
Grades 10-12
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