Math Problem Statement

Use the law of sines to solve the triangle, if possible. A = 34.9°, a = 27, b = 32.

Solution

Let's solve the triangle using the Law of Sines.

We are given:

  • A=34.9A = 34.9^\circ
  • a=27a = 27
  • b=32b = 32

Step 1: Use the Law of Sines

The Law of Sines states: sinAa=sinBb=sinCc\frac{\sin A}{a} = \frac{\sin B}{b} = \frac{\sin C}{c} Using the known values, we can set up the equation: sin34.927=sinB32\frac{\sin 34.9^\circ}{27} = \frac{\sin B}{32} Solving for sinB\sin B: sinB=32sin34.927\sin B = \frac{32 \cdot \sin 34.9^\circ}{27}

Let's calculate sinB\sin B first.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Sines

Formulas

Law of Sines: sin(A)/a = sin(B)/b = sin(C)/c

Theorems

Law of Sines

Suitable Grade Level

Grades 10-12