Math Problem Statement

Given statement is a tautology or not. [(p -> q) ^ (q -> r)] -> (p -> r)

Solution

To determine whether the given statement [(pq)(qr)](pr)[ (p \to q) \land (q \to r) ] \to (p \to r) is a tautology, let's analyze it step by step. A statement is a tautology if it is true for all possible truth values of its propositional variables.

Step 1: Expressing the statement

We are given: [(pq)(qr)](pr)[ (p \to q) \land (q \to r) ] \to (p \to r)

Step 2: Breaking down the components

  1. pqp \to q is equivalent to ¬pq\neg p \lor q.
  2. qrq \to r is equivalent to ¬qr\neg q \lor r.
  3. prp \to r is equivalent to ¬pr\neg p \lor r.

The statement becomes: [(¬pq)(¬qr)](¬pr)[ (\neg p \lor q) \land (\neg q \lor r) ] \to (\neg p \lor r)

Step 3: Analyzing the logical equivalence

The implication ABA \to B is equivalent to ¬AB\neg A \lor B. Applying this, the entire expression becomes: ¬[(¬pq)(¬qr)](¬pr)\neg [ (\neg p \lor q) \land (\neg q \lor r) ] \lor (\neg p \lor r)

Step 4: Truth table analysis

Constructing a truth table for pp, qq, and rr, and evaluating each component systematically:

ppqqrr¬pq\neg p \lor q¬qr\neg q \lor r(¬pq)(¬qr)(\neg p \lor q) \land (\neg q \lor r)¬pr\neg p \lor r[(¬pq)(¬qr)](¬pr)[ (\neg p \lor q) \land (\neg q \lor r) ] \to (\neg p \lor r)
TTTTTTTT
TTFTFFFT
TFTFTFTT
TFFFFFFT
FTTTTTTT
FTFTFFTT
FFTTTTTT
FFFTFFTT

Step 5: Conclusion

From the truth table, the statement evaluates to true for all possible truth values of pp, qq, and rr. Hence, the given statement is a tautology.


Would you like me to go over any part of the process or elaborate on specific logical steps?

Further Exploration

  1. How to systematically evaluate implications in logical statements?
  2. What is the role of truth tables in proving tautologies?
  3. Could we use logical equivalences to simplify this problem further?
  4. What are common examples of tautologies in propositional logic?
  5. How does this result apply to real-world logical reasoning?

Tip

When analyzing logical statements, always try simplifying them using equivalences like ¬(AB)¬A¬B\neg (A \land B) \equiv \neg A \lor \neg B or AB¬ABA \to B \equiv \neg A \lor B to make the analysis more straightforward.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Propositional Logic
Tautology
Logical Equivalence
Truth Tables

Formulas

Implication: A -> B is equivalent to ¬A ∨ B
De Morgan's Laws: ¬(A ∧ B) ≡ ¬A ∨ ¬B
Truth Table Analysis for evaluating logical statements

Theorems

Logical Equivalence Theorems
Truth Table Analysis for Tautology

Suitable Grade Level

Grades 10-12 or Introductory College Level