Math Problem Statement
~p →(p→q)
Solution
The expression you've provided, ~p → (p → q)
, is a logical implication involving propositions , , and a negation of , written as (read as "not p"). Let’s break down and simplify this logical expression step by step:
Step-by-Step Analysis:
-
Expression:
- : This means "not ", so the truth value of is false.
- : This is a conditional statement that means "if , then ".
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Truth Table Construction: To fully understand this expression, we need to construct a truth table for all possible truth values of and .
T | T | F | T | T |
T | F | F | F | T |
F | T | T | T | T |
F | F | T | T | T |
Interpretation:
-
Case 1: , :
- , and .
- So, , because .
-
Case 2: , :
- , and .
- So, , because .
-
Case 3: , :
- , and .
- So, , because .
-
Case 4: , :
- , and .
- So, , because .
Conclusion:
The statement is always true, which means this is a tautology. No matter the truth values of and , the whole expression will evaluate to true.
Would you like more details on how the tautology is derived or how conditionals work? Here are some related questions:
- What is the definition of a tautology in propositional logic?
- How do truth tables help verify logical statements?
- Can you explain the properties of the conditional (→) operator in more depth?
- How does the negation () of a proposition affect logical expressions?
- What are other examples of tautologies in propositional logic?
Tip: A conditional statement is false only when the antecedent is true and the consequent is false.
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Math Problem Analysis
Mathematical Concepts
Propositional Logic
Implication
Negation
Tautology
Formulas
Truth table for implication: p → q
Negation: ~p
Tautology verification using truth tables
Theorems
Tautology in Propositional Logic
Suitable Grade Level
Grades 10-12