Math Problem Statement

(p ∧ q) → p

Solution

The expression in the image is:

(pq)p(p \land q) \to p

This is a logical implication statement in propositional logic. Let's break it down:

  • pqp \land q: This means "p AND q." It's true if both pp and qq are true, and false otherwise.
  • \to: This is the implication operator, meaning "if ... then."
  • The whole expression (pq)p(p \land q) \to p reads as "if pqp \land q is true, then pp is true."

Truth Table

We can construct the truth table to see when this statement holds.

ppqqpqp \land q(pq)p(p \land q) \to p
TTTT
TFFT
FTFT
FFFT

The expression is always true, except when pqp \land q is true and pp is false, which doesn't occur in the truth table. Therefore, (pq)p(p \land q) \to p is a tautology (always true).

Would you like more details or have any questions?

Here are 5 related questions to explore:

  1. What does pqp \lor q represent in propositional logic?
  2. How do you construct the truth table for pqrp \lor q \to r?
  3. What is the contrapositive of (pq)p(p \land q) \to p?
  4. Can you show an example where (pq)p(p \lor q) \to p is false?
  5. What is the negation of the implication (pq)p(p \land q) \to p?

Tip: In logic, an implication ABA \to B is false only when AA is true and BB is false.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Propositional Logic
Implication
Conjunction
Tautology

Formulas

(p ∧ q) → p

Theorems

Implication
Tautology

Suitable Grade Level

Grades 10-12