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The uploaded image seems to show a mathematical equation related to integration, possibly involving a substitution technique for solving integrals.

Here is a breakdown of what I can see:

1. The integral being worked on involves square roots: \(\int \frac{1}{\sqrt{8t - 14}} dt\).
2. There seems to be a substitution where \( u = + \), and possibly \( du = dt \).
3. \( dv = \frac{1}{\sqrt{8t - 14}} dt \), indicating that some integration by parts or a u-substitution method is being applied.
4. The process also involves simplifying expressions like \(\frac{+^2}{\sqrt{8t - 14}}\).

To clarify the steps, I believe this problem is working through solving the integral of a function like \( \frac{1}{\sqrt{8t - 14}} \), possibly by substitution where you simplify the square root, and deal with constants like \(8t - 14\).

Would you like me to solve this integral in full or provide more detailed guidance on the steps involved?

Here are 5 related questions that may help extend your understanding:
1. What is the best strategy for integrating functions involving square roots of linear expressions?
2. How can substitution simplify integrals with complicated radicals?
3. What are some common techniques for dealing with square root functions in calculus?
4. How do we apply integration by parts in cases involving radicals?
5. What other types of substitutions can be used for integrals of this form?

**Tip**: When encountering integrals involving square roots of linear terms like \( \sqrt{8t - 14} \), completing the square or direct substitution can often simplify the process.

Solve the integral involving square roots: ∫ (1/√(8t - 14)) dt

Learn how to solve integrals involving square roots of linear expressions, like ∫ (1/√(8t - 14)) dt. This solution uses substitution methods and is suitable for college-level calculus students.

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