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The question asks to "Decompose the regular pentagon into only triangles."

To decompose a regular pentagon into triangles, follow these steps:

1. **Draw diagonals from one vertex**: Pick any vertex of the pentagon and draw lines (diagonals) to all non-adjacent vertices of the pentagon.
2. **Count the triangles**: This process divides the pentagon into exactly **3 triangles**.

For example, if you choose a vertex and connect it to two opposite (non-adjacent) vertices, you will see that the pentagon breaks down into three triangular regions.

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Here are five related questions to expand on this concept:
1. How many triangles can you decompose a regular hexagon into?
2. What is the sum of interior angles of a pentagon?
3. How does decomposing shapes into triangles help in calculating their area?
4. Can you decompose an irregular pentagon the same way as a regular one?
5. How many diagonals does a regular pentagon have?

**Tip**: The sum of the interior angles of any polygon can be calculated using the formula: \( (n-2) \times 180^\circ \), where \(n\) is the number of sides.

Decompose the regular pentagon into only triangles.

Learn how to decompose a regular pentagon into triangles by drawing diagonals from one vertex. This problem introduces geometry concepts such as polygons, triangles, and their decomposition, suitable for Grade 7 students.

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