The question asks about an 8-sided polygon (octagon) and how many triangles can be formed by drawing diagonals from a corner.

Solution:

In an 8-sided polygon, each vertex is connected to other vertices via diagonals. When drawing diagonals from one vertex, these diagonals divide the polygon into triangles.

To find the number of triangles:

1. Total vertices: An octagon has 8 vertices.

2. Triangles formed: When you pick a vertex, you can form triangles by connecting it with two other vertices. However, diagonals cannot connect directly to adjacent vertices (which are sides of the polygon itself), so we can only connect to the vertices that are not adjacent to the chosen vertex.

   Specifically, if you pick one vertex, there are 5 other vertices to which you can draw diagonals. This will result in dividing the octagon into 6 triangles.

Conclusion:

• The number of triangles formed by drawing diagonals from one corner of an 8-sided polygon (octagon) is 6.

Would you like further details, or do you have any additional questions?

Here are 5 related questions for practice:

1. How many diagonals can be drawn in a hexagon (6-sided polygon)?
2. What is the total number of triangles that can be formed by drawing all diagonals in an octagon?
3. How many diagonals can be drawn from a single vertex in a decagon (10-sided polygon)?
4. What is the number of triangles formed by drawing diagonals from a corner in a 12-sided polygon?
5. What is the formula to calculate the number of diagonals in an n-sided polygon?

Tip:

Remember that in any polygon with $n$ sides, the number of diagonals from a single vertex is $n - 3$. This helps you divide the polygon into triangles.