0,1,2,3,4,5 using these only 1 how many 3 digits number can be made

To find how many 3-digit numbers can be made using only the digits \(0, 1, 2, 3, 4, 5\), let's break this down step-by-step:

1. **The hundreds place**: 
   - It cannot be 0 (since it's a 3-digit number). 
   - So, the possible choices for the hundreds place are: \(1, 2, 3, 4, 5\). 
   - This gives us 5 possible choices for the hundreds digit.

2. **The tens place**:
   - Here, we can use any of the digits \(0, 1, 2, 3, 4, 5\), meaning we have 6 possible choices.

3. **The ones place**:
   - Similarly, any of the digits \(0, 1, 2, 3, 4, 5\) can be used here as well, giving us 6 possible choices.

Now, the total number of 3-digit numbers is the product of the number of choices for each place:

\[
5 \times 6 \times 6 = 180
\]

Therefore, **180 three-digit numbers** can be made using the digits \(0, 1, 2, 3, 4, 5\).

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Would you like more details or have any questions? Here are some related questions to explore:

1. How many 4-digit numbers can be formed using the same digits?
2. What if repetition of digits is not allowed?
3. How many 3-digit even numbers can be formed with these digits?
4. How many 3-digit numbers can be formed using only the digits \(1, 2, 3\)?
5. What if we are asked to form a number divisible by 5?

**Tip**: Always pay attention to restrictions on digit positions like the hundreds place, which cannot be zero in a multi-digit number.

Learn how to calculate the total number of 3-digit numbers that can be formed using the digits 0, 1, 2, 3, 4, 5. This problem involves basic combinatorics and counting principles, with step-by-step solutions. Suitable for students in Grades 5-7.

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