Math Problem Statement

Provide the mathematical definition for the existence of the horizontal asymptote.

According to the definition you provided, determine whether function 𝑓(π‘₯) =x^2+5x+7/4+5x^2 admit horizontal asymptotes and, if yes, write their equations

Solution

Mathematical Definition of Horizontal Asymptotes

A horizontal asymptote of a function f(x)f(x) is a horizontal line y=cy = c that the function approaches as xβ†’βˆžx \to \infty or xβ†’βˆ’βˆžx \to -\infty. Formally, if:

  • lim⁑xβ†’βˆžf(x)=c\lim_{x \to \infty} f(x) = c, then y=cy = c is a horizontal asymptote as xβ†’βˆžx \to \infty.
  • lim⁑xβ†’βˆ’βˆžf(x)=c\lim_{x \to -\infty} f(x) = c, then y=cy = c is a horizontal asymptote as xβ†’βˆ’βˆžx \to -\infty.

A function may have:

  1. One horizontal asymptote at y=cy = c as xβ†’βˆžx \to \infty and another as xβ†’βˆ’βˆžx \to -\infty,
  2. The same asymptote for both directions, or
  3. No horizontal asymptotes at all if the limits do not exist or diverge.

Determining Horizontal Asymptotes for f(x)=x2+5x+74+5x2f(x) = \frac{x^2 + 5x + 7}{4 + 5x^2}

Let's analyze the function f(x)=x2+5x+74+5x2f(x) = \frac{x^2 + 5x + 7}{4 + 5x^2} to determine whether it admits horizontal asymptotes.

Step 1: Compare the degrees of the polynomial in the numerator and denominator.

  • The numerator is x2+5x+7x^2 + 5x + 7, which has a degree of 2.
  • The denominator is 4+5x24 + 5x^2, which also has a degree of 2.

Step 2: Horizontal Asymptote Rule

For rational functions of the form P(x)Q(x)\frac{P(x)}{Q(x)}, where P(x)P(x) and Q(x)Q(x) are polynomials:

  • If the degree of P(x)P(x) is less than the degree of Q(x)Q(x), there is a horizontal asymptote at y=0y = 0.
  • If the degree of P(x)P(x) is greater than the degree of Q(x)Q(x), there is no horizontal asymptote.
  • If the degrees are equal, the horizontal asymptote is given by the ratio of the leading coefficients of P(x)P(x) and Q(x)Q(x).

Step 3: Apply to f(x)=x2+5x+74+5x2f(x) = \frac{x^2 + 5x + 7}{4 + 5x^2}

  • The degree of the numerator ( x2+5x+7x^2 + 5x + 7 ) is 2.
  • The degree of the denominator ( 4+5x24 + 5x^2 ) is 2.

Since the degrees of the numerator and denominator are equal, we compute the horizontal asymptote by finding the ratio of the leading coefficients of x2x^2 in the numerator and denominator.

  • The leading coefficient of the numerator is 1 (from x2x^2).
  • The leading coefficient of the denominator is 5 (from 5x25x^2).

Thus, the horizontal asymptote is:

y=15y = \frac{1}{5}

Conclusion

The function f(x)=x2+5x+74+5x2f(x) = \frac{x^2 + 5x + 7}{4 + 5x^2} does admit a horizontal asymptote at y=15y = \frac{1}{5}.


Would you like further clarification or details about horizontal asymptotes? Here are some related questions you might find helpful:

  1. How can I determine vertical asymptotes for rational functions?
  2. What happens to a function if the degree of the numerator is greater than the denominator?
  3. Can a rational function have both horizontal and vertical asymptotes simultaneously?
  4. How do I find the end behavior of a function using asymptotes?
  5. What are slant (oblique) asymptotes, and how do they differ from horizontal asymptotes?

Tip: For rational functions, the horizontal asymptote is especially useful in determining the behavior of the function as xx grows larger in magnitude, whether positive or negative.

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Math Problem Analysis

Mathematical Concepts

Asymptotes
Rational Functions
Limits
Degree of Polynomials

Formulas

Horizontal Asymptote Rule for Rational Functions

Theorems

Horizontal Asymptote Theorem

Suitable Grade Level

Grades 11-12