Math Problem Statement

Let f be the function defined by f(x) = (1 - 5x - 2x^2) / (3x^2 + 7) for x > 0. Which of the following is a horizontal asymptote to the graph of f?

Solution

The function provided is:

f(x)=15x2x23x2+7f(x) = \frac{1 - 5x - 2x^2}{3x^2 + 7}

The goal is to find the horizontal asymptote of this function as xx \to \infty.

Step-by-step analysis:

  1. Degrees of numerator and denominator:

    • The degree of the numerator is 2 (since the highest power of xx is x2x^2).
    • The degree of the denominator is also 2 (since the highest power of xx is also x2x^2).
  2. Horizontal Asymptote Rule:

    • If the degrees of the numerator and the denominator are the same, the horizontal asymptote is given by the ratio of the leading coefficients of the highest-degree terms.
    • The leading term of the numerator is 2x2-2x^2, and the leading term of the denominator is 3x23x^2.

    Therefore, the horizontal asymptote is:

    y=23y = \frac{-2}{3}

Thus, the horizontal asymptote of the function is y=23y = \frac{-2}{3}.

Let me know if you'd like further details or have any questions!

Here are 5 related questions for further practice:

  1. How do you find vertical asymptotes of a rational function?
  2. What happens if the degree of the numerator is greater than the degree of the denominator?
  3. How would you determine slant asymptotes in rational functions?
  4. Can a function have more than one horizontal asymptote?
  5. How does the behavior of the function near an asymptote affect the graph?

Tip: For rational functions, always compare the degrees of the numerator and denominator to quickly determine horizontal asymptotes.

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Asymptotes
Limits at Infinity

Formulas

Horizontal Asymptote = Leading Coefficient of Numerator / Leading Coefficient of Denominator

Theorems

Horizontal Asymptote Theorem

Suitable Grade Level

Grades 11-12