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The problem involves a parallelogram with a base of 6 units and a side length of 5 units. We are asked to find the corresponding height when the base is 6 units.

Looking at the diagram, there is a right triangle formed by the height (which is perpendicular to the base), one leg of 4 units, and the hypotenuse (side of the parallelogram) of 5 units. This suggests the use of the Pythagorean theorem.

Given:
- One leg = 4 units (height we need to find)
- Hypotenuse = 5 units (side of the parallelogram)
- Other leg is not relevant for this calculation.

Using the Pythagorean theorem:
\[
\text{Hypotenuse}^2 = \text{Leg}_1^2 + \text{Leg}_2^2
\]
Substitute values:
\[
5^2 = 4^2 + \text{height}^2
\]
\[
25 = 16 + \text{height}^2
\]
\[
\text{height}^2 = 25 - 16 = 9
\]
\[
\text{height} = \sqrt{9} = 3
\]

Thus, the height corresponding to the base of 6 units is **4 units**.

The correct answer is **C. 4 units**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How does the Pythagorean theorem apply to different shapes like triangles or parallelograms?
2. What are the other properties of a parallelogram?
3. How would the height change if the base length was increased?
4. Can the height of a parallelogram be greater than the side length?
5. How do we calculate the area of a parallelogram?

**Tip**: Always check for right triangles in geometric figures like parallelograms, as they often help in finding unknown lengths or heights.

If the side that is 6 units long is the base of this parallelogram, what is its corresponding height?

Learn how to find the height of a parallelogram with a base of 6 units and a side of 5 units using the Pythagorean theorem. A step-by-step explanation for students in Grades 6-8, including geometry concepts and the Pythagorean theorem.

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