Math Problem Statement

1.Hitunglah Jelaskan banyak kelas,panjang kelas,berdasarkan perhitungan,susun tabel distribusi frekuensi berkelompok

Hitunglah banyak kelas, panjang kelas berdasarkan perhitungan, susun tabel distribusi frekuensi berkelompok dari data nilai ujian siswa sebanyak 90 orang.

Solution

To solve the problem of creating a grouped frequency distribution table from the data provided in the image, let's follow these steps:

Step 1: Extract the data

Here is the data extracted from the image:

  • 70, 40, 69, 71, 65, 52, 90, 48, 72, 82, 76
  • 88, 79, 42, 55, 80, 71, 81, 85, 91, 64
  • 69, 61, 88, 46, 50, 65, 62, 77, 60
  • 87, 84, 73, 66, 91, 74, 75, 63, 90, 83
  • 66, 51, 49, 81, 84, 92, 61, 72, 77, 55
  • 71, 82, 74, 89, 78, 58, 78, 33, 53
  • 82, 73, 58, 52, 68, 76, 85, 88, 77

Step 2: Calculate the class interval and number of classes

The number of classes can be determined by Sturges' formula: k=1+3.322lognk = 1 + 3.322 \log n where nn is the number of data points. In this case, n=90n = 90.

k=1+3.322log907.46k8k = 1 + 3.322 \log 90 \approx 7.46 \Rightarrow k \approx 8 So, we will have 8 classes.

Now, calculate the range of the dataTo solve the problem of creating a grouped frequency distribution table from the data provided in the image, let's follow these steps:

Step 1: Extract the data

Here is the data extracted from the image:

  • 70, 40, 69, 71, 65, 52, 90, 48, 72, 82, 76
  • 88, 79, 42, 55, 80, 71, 81, 85, 91, 64
  • 69, 61, 88, 46, 50, 65, 62, 77, 60
  • 87, 84, 73, 66, 91, 74, 75, 63, 90, 83
  • 66, 51, 49, 81, 84, 92, 61, 72, 77, 55
  • 71, 82, 74, 89, 78, 58, 78, 33, 53
  • 82, 73, 58, 52, 68, 76, 85, 88, 77

Step 2: Calculate the class interval and number of classes

The number of classes can be determined by Sturges' formula: k=1+3.322lognk = 1 + 3.322 \log n where nn is the number of data points. In this case, n=90n = 90.

k=1+3.322log907.46k8k = 1 + 3.322 \log 90 \approx 7.46 \Rightarrow k \approx 8 So, we will have 8 classes.

Now, calculate the range of the Range=Max valueMin value=9233=59\text{Range} = \text{Max value} - \text{Min value} = 92 - 33 = 59 The class width is given by: Class width=Rangek=5987.38Class width=8\text{Class width} = \frac{\text{Range}}{k} = \frac{59}{8} \approx 7.38 \Rightarrow \text{Class width} = 8 So, we will use a class width of 8.

Step 3: Construct the frequency distribution table

The class intervals will start from the minimum value and increase by the class width of 8. Here's how the classes look:

Class IntervalFrequency
33 – 40
41 – 48
49 – 56
57 – 64
65 – 72
73 – 80
81 – 88
89 – 96

Next, we will count how many values fall into each class interval.

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Math Problem Analysis

Mathematical Concepts

Statistics
Grouped Frequency Distribution
Data Analysis

Formulas

Sturges' formula: k = 1 + 3.322 log n
Class width = (Max value - Min value) / Number of classes

Theorems

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Suitable Grade Level

Grades 10-12