Math Problem Statement

Directions: Show all appropriate work. Write formulas used before plugging in numbers; include correct notation on answers; indicate which answer is which when more than 1 thing is asked. Circle all final numerical answers.

  1. Following is data collected of test scores from a sample of students in Mrs. Mayer’s Math 180 class.
    67, 73, 64, 94, 87, 78, 56, 76, 88, 48, 79, 51, 28, 75, 84, 89, 75, 67, 77, 98, 80, 38, 53, 62 a. Find an appropriate class width for making a frequency distribution with 6 classes. b. Make a relative frequency distribution using 6 classes & the width you found in part a. Be sure fill in all columns of the given table, round the last column to 1 decimal place in the %. (I gave you your 1st lower limit) Class Limits Class Boundaries Tally Frequency 28 -
    Relative Frequency (give as a %) c. Construct a histogram using the frequency distribution from part (b).

Solution

1. Data Collected of Test Scores from Mrs. Mayer’s Class:

Given data### 1. Data Collected of Test Scores from Mrs. Mayer’s Class:

Given
67, 73, 64, 94, 87, 78, 56, 76, 88, 48, 79, 51, 28, 75, 84, 89, 75, 67, 77, 98, 80, 38, 53, 62

a. Finding the Class Width

To calculate the class width, we use the formula:

Class Width=RangeNumber of Classes\text{Class Width} = \frac{\text{Range}}{\text{Number of Classes}}

  1. Range: The range is the difference between the highest and lowest values in the data set.

Range=MaxMin=9828=70\text{Range} = \text{Max} - \text{Min} = 98 - 28 = 70

  1. Number of Classes: We are asked to create 6 classes.

Class Width=70611.67\text{Class Width} = \frac{70}{6} \approx 11.67

We round the class width to the nearest whole number. So the class width is 12.

b. Creating a Relative Frequency Distribution with 6 Classes

We start the first class at the given lower limit of 28 and then add the class width of 12 for the next classes. The table structure is:

Class LimitsClass BoundariesTallyFrequencyRelative Frequency (%)
28 - 3927.5 - 39.5
40 - 5139.5 - 51.5
52 - 6351.5 - 63.5
64 - 7563.5 - 75.5
76 - 8775.5 - 87.5
88 - 9987.5 - 99.5

Now, we tally the data### 1. Data Collected of Test Scores from Mrs. Mayer’s Class:

Given
67, 73, 64, 94, 87, 78, 56, 76, 88, 48, 79, 51, 28, 75, 84, 89, 75, 67, 77, 98, 80, 38, 53, 62

a. Finding the Class Width

To calculate the class width, we use the formula:

Class Width=RangeNumber of Classes\text{Class Width} = \frac{\text{Range}}{\text{Number of Classes}}

  1. Range: The range is the difference between the highest and lowest values in the data set.

Range=MaxMin=9828=70\text{Range} = \text{Max} - \text{Min} = 98 - 28 = 70

  1. Number of Classes: We are asked to create 6 classes.

Class Width=70611.67\text{Class Width} = \frac{70}{6} \approx 11.67

We round the class width to the nearest whole number. So the class width is 12.

b. Creating a Relative Frequency Distribution with 6 Classes

We start the first class at the given lower limit of 28 and then add the class width of 12 for the next classes. The table structure is:

Class LimitsClass BoundariesTallyFrequencyRelative Frequency (%)
28 - 3927.5 - 39.5
40 - 5139.5 - 51.5
52 - 6351.5 - 63.5
64 - 7563.5 - 75.5
76 - 8775.5 - 87.5
88 - 9987.5 - 99.5

Now, we tally the

Tallying the Data:

  • 28 - 39: 28, 38 (2)
  • 40 - 51: 48, 51 (2)
  • 52 - 63: 56, 53, 62 (3)
  • 64 - 75: 67, 64, 73, 75, 75, 67 (6)
  • 76 - 87: 78, 76, 84, 87, 79, 80, 77 (7)
  • 88 - 99: 94, 88, 98, 89 (4)

Filling in the table:

Class LimitsClass BoundariesTallyFrequencyRelative Frequency (%)
28 - 3927.5 - 39.5

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Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Distribution
Relative Frequency
Histograms

Formulas

Class Width = (Max - Min) / Number of Classes
Relative Frequency (%) = (Frequency / Total Data Points) * 100

Theorems

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Suitable Grade Level

Grades 9-12