Here is the graph of the quadratic function $f(x) = (x - 1)^2$. The parabola has its vertex at $(1, 0)$, and it opens upward.

Do you want any further details or have any questions?

Here are five related questions you might find useful:

1. How do you find the vertex of a general quadratic function?
2. What is the significance of the axis of symmetry in a parabola?
3. How would the graph change if the function was $f(x) = -(x - 1)^2$?
4. Can you determine the y-intercept algebraically?
5. How would this function shift if we added a constant to it, say $f(x) = (x - 1)^2 + 3$?

Tip: The vertex form of a quadratic function makes it easy to identify shifts, direction, and the vertex of the parabola.