Math Problem Statement

graph the relation represented by the following parametric equations x=2t y=t+1 -2<t<2 please show all your work

Solution

We are tasked with graphing the relation represented by the parametric equations:

x=2tx = 2t y=t+1y = t + 1 for the parameter tt in the range 2<t<2-2 < t < 2.

Step 1: Understanding the Parametric Equations

In a parametric equation, xx and yy are both expressed in terms of a third variable, tt, which represents the parameter.

  • x=2tx = 2t
  • y=t+1y = t + 1

We need to eliminate the parameter tt to obtain a Cartesian equation relating xx and yy.

Step 2: Eliminate the Parameter

To eliminate tt, solve for tt in terms of xx from the first equation: x=2t    t=x2x = 2t \implies t = \frac{x}{2}

Substitute this expression for tt into the second equation: y=t+1=x2+1y = t + 1 = \frac{x}{2} + 1

Thus, the Cartesian equation is: y=x2+1y = \frac{x}{2} + 1

This is the equation of a straight line with slope 12\frac{1}{2} and y-intercept 1.

Step 3: Set Bounds for tt

The parameter tt is restricted by the inequality 2<t<2-2 < t < 2. Substituting these bounds into the equation for xx, we find the corresponding limits for xx:

x=2(2)=4andx=2(2)=4x = 2(-2) = -4 \quad \text{and} \quad x = 2(2) = 4

Thus, xx varies from 4-4 to 44.

Step 4: Find Points to Plot

Now, we can create a table of values by substituting various values of tt within the given range into the parametric equations.

ttx=2tx = 2ty=t+1y = t + 1
2-24-41-1
1-12-200
000011
112222
224433

These points are: (4,1),(2,0),(0,1),(2,2),(4,3)(-4, -1), (-2, 0), (0, 1), (2, 2), (4, 3).

Step 5: Graph the Relation

  1. Plot the points (4,1),(2,0),(0,1),(2,2),(4,3)(-4, -1), (-2, 0), (0, 1), (2, 2), (4, 3).
  2. Draw a straight line passing through these points since the equation y=x2+1y = \frac{x}{2} + 1 is a straight line.
  3. Ensure that the line only extends from x=4x = -4 to x=4x = 4 as determined by the bounds on tt.

The graph will be a segment of the line y=x2+1y = \frac{x}{2} + 1 between x=4x = -4 and x=4x = 4.

Conclusion

The graph represents a straight line segment from the point (4,1)(-4, -1) to (4,3)(4, 3). The slope of the line is 12\frac{1}{2}, and the y-intercept is 1.

Do you want further details or explanations on any part of this solution? Here are some related questions to expand your understanding:

  1. What is the significance of the slope in the line equation y=x2+1y = \frac{x}{2} + 1?
  2. How would the graph change if the range of tt was 3<t<3-3 < t < 3?
  3. What is the effect of changing the parametric equation for xx?
  4. How can we convert other parametric equations into Cartesian form?
  5. How can you check if a given set of parametric equations represents a straight line?

Tip: When graphing parametric equations, always check if you can convert them to Cartesian form to gain a better understanding of the shape of the graph.

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Math Problem Analysis

Mathematical Concepts

Parametric Equations
Linear Equations
Cartesian Coordinates

Formulas

x = 2t
y = t + 1
y = (x / 2) + 1 (after eliminating the parameter t)

Theorems

Conversion of parametric equations to Cartesian form

Suitable Grade Level

Grades 9-12