The linear equation given is $y = 3x + 1$.

This is in the slope-intercept form $y = mx + b$, where:

• $m = 3$ is the slope,
• $b = 1$ is the y-intercept.

Steps to graph the line:

1. Start with the y-intercept (0, 1): Plot the point at $(0, 1)$ on the y-axis.
2. Use the slope: The slope is $3$, meaning that for every increase of 1 unit in the x-direction, the y-coordinate increases by 3 units. So, from $(0, 1)$, move 1 unit to the right and 3 units up to find another point $(1, 4)$.
3. Plot another point: Use the slope again, or go back by moving 1 unit left and 3 units down to get another point $(-1, -2)$.
4. Draw the line: Connect these points with a straight line.

This line represents the equation $y = 3x + 1$.

Would you like further details on graphing or on interpreting linear equations?

Here are 5 related questions:

1. What happens if you change the slope in the equation?
2. How do you find the x-intercept of a linear equation?
3. What is the relationship between the slope and the steepness of the line?
4. How do you determine the direction of a line based on the sign of the slope?
5. How can you graph linear inequalities from equations like this one?

Tip: The y-intercept is always where the line crosses the y-axis, and it's a quick way to start graphing any linear equation.