The equation provided is $y = 3x - 8$, which is in slope-intercept form $y = mx + b$, where:

• $m = 3$ is the slope, meaning the line rises 3 units for every 1 unit it moves to the right.
• $b = -8$ is the y-intercept, meaning the line crosses the y-axis at $y = -8$.

To graph this line:

1. Start by plotting the y-intercept, $(0, -8)$.
2. Use the slope $m = 3$ to find another point: From $(0, -8)$, move 1 unit to the right (along the x-axis) and 3 units up. This gives the point $(1, -5)$.
3. Draw a line through these two points.

Would you like me to provide further details or explanations?

Here are five related questions to expand this topic:

1. How do you determine the slope from a line given two points?
2. What does it mean when the slope of a line is negative?
3. How can you find the x-intercept of a linear equation?
4. What happens to the graph if the slope becomes smaller, such as $y = \frac{1}{2}x - 8$?
5. Can a linear equation have no y-intercept?

Tip: The slope of a line describes its steepness. A higher slope means a steeper line, while a smaller slope results in a flatter line.