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The equation provided is \( y = 3x - 8 \), which is in slope-intercept form \( y = mx + b \), where:

- \( m = 3 \) is the slope, meaning the line rises 3 units for every 1 unit it moves to the right.
- \( b = -8 \) is the y-intercept, meaning the line crosses the y-axis at \( y = -8 \).

To graph this line:
1. Start by plotting the y-intercept, \( (0, -8) \).
2. Use the slope \( m = 3 \) to find another point: From \( (0, -8) \), move 1 unit to the right (along the x-axis) and 3 units up. This gives the point \( (1, -5) \).
3. Draw a line through these two points.

Would you like me to provide further details or explanations?

Here are five related questions to expand this topic:
1. How do you determine the slope from a line given two points?
2. What does it mean when the slope of a line is negative?
3. How can you find the x-intercept of a linear equation?
4. What happens to the graph if the slope becomes smaller, such as \( y = \frac{1}{2}x - 8 \)?
5. Can a linear equation have no y-intercept?

**Tip:** The slope of a line describes its steepness. A higher slope means a steeper line, while a smaller slope results in a flatter line.

Learn how to graph the linear equation y = 3x - 8 step-by-step. This problem covers key algebraic concepts, including slope-intercept form and graphing a line based on its slope and y-intercept. Suitable for students in Grades 8-10.

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