import numpy as np import matplotlib.pyplot as plt

Define the function y = 3x + 1

x = np.linspace(-10, 10, 400) y = 3 * x + 1

Plot the graph

plt.figure(figsize=(8, 6)) plt.plot(x, y, label="y = 3x + 1", linewidth=2) plt.axhline(0, color='black', linewidth=0.8, linestyle='--') # x-axis plt.axvline(0, color='black', linewidth=0.8, linestyle='--') # y-axis plt.title("Graph of y = 3x + 1", fontsize=14) plt.xlabel("x", fontsize=12) plt.ylabel("y", fontsize=12) plt.grid(alpha=0.4) plt.legend(fontsize=12) plt.show() <<ImageDisplayed>>successHere is the graph of the function $y = 3x + 1$. The line has a slope of 3 and a y-intercept at $(0, 1)$.

Would you like to explore further details or ask any questions about this function?

Related Questions:

1. What is the slope and how does it affect the graph?
2. How can I find the x-intercept of $y = 3x + 1$?
3. What changes occur in the graph if the slope is altered?
4. How does the y-intercept influence the position of the line?
5. Can you explain the general form of a linear equation and its components?

Tip:

To understand the impact of slope and intercept on a graph, try visualizing the effects by changing their values!