The equation shown in the image is $y = 3x + 1$, which represents a linear equation in slope-intercept form $y = mx + b$. Here, $m = 3$ is the slope, and $b = 1$ is the y-intercept (the point where the line crosses the y-axis).

Steps to graph the equation:

1. Plot the y-intercept: The y-intercept is $(0, 1)$, so the first point to plot is at $y = 1$ on the y-axis.

2. Use the slope: The slope $m = 3$ means that for every 1 unit you move to the right on the x-axis, you move 3 units up on the y-axis. Starting from $(0, 1)$, you can plot another point by moving 1 unit to the right (to $x = 1$) and 3 units up (to $y = 4$), so the next point will be $(1, 4)$.

3. Draw the line: After plotting these two points, you can draw a straight line through them, which represents the equation.

Let me know if you would like more details on the graphing process or any other questions!

Here are 5 related questions:

1. How would the graph change if the slope were negative, like in $y = -3x + 1$?
2. What happens to the line if we change the y-intercept to $b = 0$, giving $y = 3x$?
3. How would you graph a vertical line, such as $x = 2$?
4. What is the slope of a horizontal line, like $y = 5$?
5. Can you find the x-intercept of the line $y = 3x + 1$?

Tip: The slope of a line tells you how steep the line is. A larger slope results in a steeper line, while a smaller slope results in a flatter line!