The image you've uploaded contains a linear equation $y = 3x - 1$, a table with columns for $x$ and $y$, and a graph with axes prepared for plotting points.

Here’s how we can proceed:

Step 1: Fill the table

We will substitute different values for $x$ into the equation $y = 3x - 1$ and compute the corresponding values of $y$.

1. If $x = -1$: $y = 3(-1) - 1 = -3 - 1 = -4$ So, $(-1, -4)$ is one point.

2. If $x = 0$: $y = 3(0) - 1 = 0 - 1 = -1$ So, $(0, -1)$ is another point.

3. If $x = 1$: $y = 3(1) - 1 = 3 - 1 = 2$ So, $(1, 2)$ is another point.

4. If $x = 2$: $y = 3(2) - 1 = 6 - 1 = 5$ So, $(2, 5)$ is another point.

The table would be: