The equation provided is $y = 8x - 10$. To graph this line, we need to identify the y-intercept and use the slope to find additional points on the graph.

Step 1: Identify the y-intercept

The y-intercept is the point where the line crosses the y-axis. For the equation $y = 8x - 10$, the y-intercept is -10. This gives us the point $(0, -10)$.

Step 2: Use the slope to find another point

The slope of the line is given by the coefficient of $x$, which is 8. This means that for every 1 unit increase in $x$, $y$ increases by 8 units.

Starting from the y-intercept $(0, -10)$:

• Increase $x$ by 1: $x = 1$
• Increase $y$ by 8: $y = -10 + 8 = -2$

So, another point on the line is $(1, -2)$.

Points on the graph:

1. $(0, -10)$
2. $(1, -2)$

You can plot these points on the graph and draw a straight line through them to represent the equation.

Would you like more details or have any questions about this?

Here are 8 related questions:

1. How do you determine the slope from a given equation?
2. What is the significance of the y-intercept in a linear equation?
3. How would the graph change if the slope were negative?
4. Can you find another point on the line using the slope?
5. How do you graph a line if the equation is not in slope-intercept form?
6. What happens to the graph if the y-intercept is positive?
7. How would you determine if two lines are parallel?
8. What is the general form of a linear equation?

Tip: Remember that the slope determines the steepness and direction of a line. A larger slope means a steeper line, while a negative slope indicates the line slopes downwards.