Describe how the graph of ​h(x)equalsminus3xplus3 can be obtained from one of the basic graphs. Then graph the function.

Here is the graph of \( h(x) = -3x + 3 \). As described, the line has a slope of \(-3\), making it steep and slanting downward, and it crosses the y-axis at \( (0, 3) \).

Do you have any further questions, or would you like additional details about how the graph was constructed?

Here are 5 related questions to deepen your understanding:
1. How would the graph change if the slope were positive, say \( h(x) = 3x + 3 \)?
2. What is the effect on the graph if the y-intercept is changed to \( -3 \)?
3. How do you find the x-intercept of this line from the equation?
4. Can you describe how to write the equation of a line given its slope and a point on the line?
5. How does the slope of the line impact the steepness of the graph?

**Tip**: When graphing linear equations, always identify the slope and y-intercept first to quickly sketch the line.

Describe how the graph of ​h(x) equals minus 3x plus 3 can be obtained from one of the basic graphs. Then graph the function.

Understand how to graph the linear equation h(x) = -3x + 3. Learn the key concepts of slope and y-intercept, including how the negative slope impacts the steepness of the line and how to identify the intercept points. Suitable for students in Grades 8-10.

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