The equation you need to graph is $y = -x - 3$. This is in slope-intercept form, $y = mx + b$, where $m$ is the slope and $b$ is the y-intercept.

• The slope $m$ is -1, meaning the line goes down 1 unit for every 1 unit it moves to the right.
• The y-intercept $b$ is -3, so the line crosses the y-axis at $(0, -3)$.

Steps to graph:

1. Start by plotting the y-intercept at $(0, -3)$.
2. Use the slope, which is -1. From the point $(0, -3)$, move 1 unit right and 1 unit down to find another point, $(1, -4)$.
3. Draw a straight line through these two points.

Would you like a detailed explanation of how this graph relates to the line's equation?

Here are some related questions:

1. What does the slope of a line represent?
2. How does the y-intercept affect the position of a line on the graph?
3. What would the graph look like if the slope were positive instead of negative?
4. How can you use two points to find the slope of a line?
5. What happens to the graph if you change the y-intercept value?

Tip: Always check that you plot enough points to ensure the line is accurate, especially when the slope is not an integer.