Math Problem Statement

give me a 5/10 medium complex graphing question that applies in the real world

Solution

Here's a medium-complexity graphing question that applies to the real world:

Question:

A company produces and sells smartphones. The company's total cost (including fixed and variable costs) to produce xx smartphones can be modeled by the equation:

C(x)=5000+150xC(x) = 5000 + 150x

Where:

  • C(x)C(x) is the total cost in dollars,
  • xx is the number of smartphones produced.

The company sells each smartphone for $300, so the revenue function is given by:

R(x)=300xR(x) = 300x

  1. Graph the cost function C(x)C(x) and the revenue function R(x)R(x) on the same coordinate plane for xx values between 0 and 100.

  2. Determine the break-even point, where the company's revenue equals its costs.

  3. Shade the region where the company is making a profit.

  4. What is the minimum number of smartphones the company must produce to make a profit?


Would you like any details or further clarifications on this question?

Here are 5 related questions you could explore:

  1. How would the graph change if the fixed cost increased to $7000?
  2. What if the company decides to sell smartphones at $250 each, how does that affect the break-even point?
  3. How would the profit region shift if the variable cost per smartphone increased to $200?
  4. If the company wants to earn a profit of $20,000, how many smartphones must it sell?
  5. What is the significance of the slope of the revenue and cost functions in this scenario?

Tip: In real-world graphing problems, always pay attention to the intersections of cost and revenue to identify break-even points and profit regions.

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Math Problem Analysis

Mathematical Concepts

Linear Functions
Cost and Revenue Analysis
Graphing
Break-Even Point
Profit Calculation

Formulas

Cost function: C(x) = 5000 + 150x
Revenue function: R(x) = 300x
Break-even point: C(x) = R(x)

Theorems

Basic Linear Equation Theorem

Suitable Grade Level

Grades 10-12