Math Problem Statement

Every vertex in a graph G has either degree 1 or degree 3. Knowing that the graph has 10 edges and exactly 2 nodes of degree 3 show that it cannot have 5 connected components.

Solution

To analyze the problem, let’s break down the given information:

  1. Degrees of vertices: In graph GG, every vertex has either degree 1 or degree 3.
  2. Total edges: The graph has 10 edges.
  3. Vertices of degree 3: There are exactly 2 vertices of degree 3.

Let’s denote:

  • n1n_1: the number of vertices of degree 1.
  • n3=2n_3 = 2: the number of vertices of degree 3.

Step 1: Calculate the total degree

The sum of the degrees of all vertices in a graph is equal to twice the number of edges. Therefore, we can write:

Total degree=2×Number of edges=2×10=20.\text{Total degree} = 2 \times \text{Number of edges} = 2 \times 10 = 20.

The total degree can also be expressed in terms of the degrees of the vertices:

Total degree=1×n1+3×n3=n1+3×2=n1+6.\text{Total degree} = 1 \times n_1 + 3 \times n_3 = n_1 + 3 \times 2 = n_1 + 6.

Setting these two expressions for total degree equal gives:

n1+6=20.n_1 + 6 = 20.

Solving for n1n_1:

n1=206=14.n_1 = 20 - 6 = 14.

Step 2: Count the total number of vertices

The total number of vertices nn in the graph is the sum of the vertices of degree 1 and degree 3:

n=n1+n3=14+2=16.n = n_1 + n_3 = 14 + 2 = 16.

Step 3: Components and edges

Now, consider the connectivity of the graph. A connected component is formed by vertices connected through edges.

For kk components, the number of edges EE can be calculated as follows. The minimum number of edges required to connect nn vertices in kk components is:

Emin=nk.E_{\text{min}} = n - k.

In our case, since E=10E = 10 and n=16n = 16:

Emin=16k.E_{\text{min}} = 16 - k.

Setting this equal to the given number of edges:

16k10    k6.16 - k \leq 10 \implies k \geq 6.

Conclusion

Since kk must be at least 6, having 5 connected components (i.e., k=5k = 5) contradicts this condition. Therefore, the graph cannot have 5 connected components.

Summary

We have shown that a graph GG with 10 edges, where every vertex has either degree 1 or degree 3, and exactly 2 vertices of degree 3, cannot have 5 connected components.

Would you like further details or have any questions? Here are some related questions for consideration:

  1. How would the scenario change if the number of edges were increased?
  2. What would happen if there were 3 vertices of degree 3 instead of 2?
  3. Can you describe the structure of a possible graph with the given conditions?
  4. What are the implications of having vertices with higher degrees?
  5. How does the connectivity of a graph affect its components?

Tip: Always verify the relationship between edges and vertices when dealing with graph components; it can reveal constraints on the structure of the graph.

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Math Problem Analysis

Mathematical Concepts

Graph Theory
Degree of Vertices
Connectivity

Formulas

Total degree = 2 * Number of edges
E_min = n - k

Theorems

Handshaking Lemma

Suitable Grade Level

Grades 10-12