https://file.aiquickdraw.com/mathbot/file/17271969556707zegdxou.jpg

To solve the problem, we need to reflect the point \( Q(-1, 6) \) over the line \( y = x \).

### Reflection over the line \( y = x \):
- The rule for reflecting a point \( (x, y) \) over the line \( y = x \) is to swap the coordinates of the point.
- Therefore, the image of \( Q(-1, 6) \) after the reflection will be at the point \( Q'(6, -1) \).

Now, to graph it:
1. Locate the point \( Q'(6, -1) \) on the grid.
2. Mark the point.

Would you like me to generate a graph with this reflection, or do you have any further questions?

Here are 5 related questions to further your understanding:
1. What is the rule for reflecting a point over the line \( y = -x \)?
2. How would you reflect the point \( Q(-1, 6) \) over the x-axis?
3. How can we algebraically verify that the reflection is correct?
4. What is the general transformation rule for reflecting over the line \( y = mx + b \)?
5. How would the reflection change if the line was \( y = 2x \)?

**Tip:** Whenever you reflect a point over the line \( y = x \), just swap the coordinates. This rule makes reflections quick and easy!

Graph the image of Q(-1, 6) after a reflection over the line y = x.

Learn how to reflect the point Q(-1, 6) over the line y = x using the rule of swapping coordinates. Understand how the image of Q is transformed to Q'(6, -1) with a visual step-by-step explanation.

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