Math Problem Statement

1/3 × 128

Given a geometric sequence with U3 = 12 and U6 = 96, find the first term, common ratio, 8th term, and sum of the first 6 terms.

Solution

The image shows a geometric sequence problem where you are provided with the 3rd term (U3=12U_3 = 12) and the 6th term (U6=96U_6 = 96) of the sequence. The tasks are to find:

a) The first term (aa)
b) The common ratio (rr)
c) The 8th term (U8U_8)
d) The sum of the first 6 terms (S6S_6)

Let's solve these step by step.

Step 1: General form of a geometric sequence

The nn-th term of a geometric sequence is given by: Un=arn1U_n = a \cdot r^{n-1}

Step 2: Use the given terms

We know the following:

  • U3=ar2=12U_3 = a \cdot r^2 = 12
  • U6=ar5=96U_6 = a \cdot r^5 = 96

We now have two equations: ar2=12(1)a \cdot r^2 = 12 \quad \text{(1)} ar5=96(2)a \cdot r^5 = 96 \quad \text{(2)}

Step 3: Solve for rr

Divide equation (2) by equation (1): ar5ar2=9612\frac{a \cdot r^5}{a \cdot r^2} = \frac{96}{12} This simplifies to: r3=8r=2r^3 = 8 \quad \Rightarrow \quad r = 2

Step 4: Find aa

Substitute r=2r = 2 into equation (1): a22=12a4=12a=3a \cdot 2^2 = 12 \quad \Rightarrow \quad a \cdot 4 = 12 \quad \Rightarrow \quad a = 3

Step 5: Find the 8th term (U8U_8)

Using the formula for the nn-th term: U8=ar7=327=3128=384U_8 = a \cdot r^{7} = 3 \cdot 2^7 = 3 \cdot 128 = 384

Step 6: Find the sum of the first 6 terms (S6S_6)

The sum of the first nn terms of a geometric sequence is given by: Sn=a1rn1rS_n = a \cdot \frac{1 - r^n}{1 - r} For S6S_6: S6=312612=31641=363=189S_6 = 3 \cdot \frac{1 - 2^6}{1 - 2} = 3 \cdot \frac{1 - 64}{-1} = 3 \cdot 63 = 189

Final Answers:

a) The first term a=3a = 3
b) The common ratio r=2r = 2
c) The 8th term U8=384U_8 = 384
d) The sum of the first 6 terms S6=189S_6 = 189

Would you like further details on any part of the solution or have any questions?


Here are 5 related questions to deepen understanding:

  1. How do you calculate the sum of an infinite geometric series?
  2. What would the 10th term of this geometric sequence be?
  3. If the ratio was r=3r = 3, how would the sequence change?
  4. How can you find the common ratio if you're given non-consecutive terms?
  5. What is the difference between an arithmetic sequence and a geometric sequence?

Tip: In a geometric sequence, the ratio between consecutive terms is always constant, which helps in solving problems when some terms are unknown.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Exponential Growth

Formulas

nth term formula: U_n = a * r^(n-1)
Sum of geometric series: S_n = a * (1 - r^n) / (1 - r)

Theorems

Geometric Sequence Theorem

Suitable Grade Level

Grades 9-11