Math Problem Statement

Find the partial sum S7 for the geometric sequence with a=5, r=3

Solution

To find the 7th partial sum S7S_7 of a geometric sequence, we use the formula for the sum of the first nn terms of a geometric sequence:

Sn=a(1rn)1rS_n = \frac{a(1 - r^n)}{1 - r}

where:

  • aa is the first term,
  • rr is the common ratio, and
  • nn is the number of terms to sum.

Given:

  • a=5a = 5,
  • r=3r = 3, and
  • n=7n = 7,

we can substitute these values into the formula:

S7=5(137)13S_7 = \frac{5(1 - 3^7)}{1 - 3}

Now, calculate 373^7:

37=21873^7 = 2187

Substitute this into the equation:

S7=5(12187)2S_7 = \frac{5(1 - 2187)}{-2} S7=5(2186)2S_7 = \frac{5(-2186)}{-2} S7=109302S_7 = \frac{-10930}{-2} S7=5465S_7 = 5465

So, the 7th partial sum is S7=5465S_7 = 5465.

Would you like more details or have any questions? Here are some related questions:

  1. How does the formula for the sum of a geometric sequence change if r<1|r| < 1?
  2. What happens to the sum as the number of terms nn increases for a geometric sequence with r>1|r| > 1?
  3. How do you find the sum of an infinite geometric series?
  4. How would you find the nth term of a geometric sequence?
  5. What is the relationship between the common ratio rr and the growth rate of the sequence?

Tip: If the common ratio rr is greater than 1, the sequence grows rapidly, which leads to very large sums as nn increases.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Partial Sums
Exponents

Formulas

S_n = a(1 - r^n) / (1 - r)

Theorems

Sum of a geometric sequence

Suitable Grade Level

Grades 9-12