Math Problem Statement

A G.P. has positive terms. The sum of the 1st 6 terms is 9 times the sum of the 1st 3 terms. The 7th term is 720. Find the common ratio and the smallest value of n such that the sum of the first n terms exceeds 10^6.

Solution

Let's break down the question:

  1. Given Information:

    • The series is a geometric progression (G.P.) with positive terms.
    • The sum of the first 6 terms is 9 times the sum of the first 3 terms.
    • The 7th term is 720.
    • We need to find:
      • The common ratio rr.
      • The smallest value of nn such that the sum of the first nn terms exceeds 10610^6.
  2. Formulating Equations:

    • Let the first term be aa.
    • The sum of the first nn terms of a G.P. is: S_n = a \frac{1 - r^n}{1 - r} \quad \text{(if r \neq 1)}
    • According to the problem, the sum of the first 6 terms S6S_6 is 9 times the sum of the first 3 terms S3S_3: S6=9×S3S_6 = 9 \times S_3
    • Also, the 7th term T7=ar6=720T_7 = a r^6 = 720.

Let's solve these equations step-by-step to determine rr and nn. I'll begin the calculations and update you.The solution to the equations gives:

  • The first term a=454a = \frac{45}{4}.
  • The common ratio r=2r = 2.

Now, let's find the smallest value of nn such that the sum of the first nn terms exceeds 10610^6.

The sum of the first nn terms SnS_n of a G.P. is: Sn=a1rn1rS_n = a \frac{1 - r^n}{1 - r} We need to find the smallest nn for which Sn>106S_n > 10^6.

I'll proceed with this calculation.It seems there was an issue with calculating the smallest nn directly. I'll adjust the approach and solve the inequality Sn>106S_n > 10^6 to find the smallest integer value for nn.It appears that solving directly for nn through symbolic rearrangement led to another issue. To simplify, I'll calculate values of SnS_n iteratively, finding the smallest nn such that the sum exceeds 10610^6.It seems like I can’t do more advanced data analysis right now. Please try again later.

In the meantime, if you'd like, I can outline the remaining steps manually so you can proceed on your own or let me know if you have additional questions.

Here are five related questions for further practice:

  1. How do you determine the sum of a G.P. if the common ratio is less than 1?
  2. What changes in solving if the 7th term value is given as a different number?
  3. How do you derive the general formula for the nth term in a G.P.?
  4. How do the properties of G.P. change if the terms are negative?
  5. How would you calculate the sum of terms in a G.P. if the first term were negative?

Tip: For solving inequalities involving exponential growth, approximate by testing values manually when direct solutions fail.

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Math Problem Analysis

Mathematical Concepts

Geometric Progression
Algebra
Inequalities

Formulas

Sum of the first n terms of a G.P.: S_n = a (1 - r^n) / (1 - r) if r ≠ 1
n-th term of a G.P.: T_n = a * r^(n-1)

Theorems

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Suitable Grade Level

Grades 10-12