Math Problem Statement

The 7th term of a geometric sequence is 6, and the common ratio is 1/3. (a) Find the exact value of the first term of the sequence. (b) Find the exact value of the 15th term of the sequence. (c) Find the exact value of the sum of the first 10 terms of the sequence.

Solution

The problem you provided deals with a geometric sequence where:

  • The 7th term is given as 66,
  • The common ratio rr is 13\frac{1}{3}.

Part (a): Finding the exact value of the first term of the sequence

In a geometric sequence, the formula for the nn-th term is:

an=a1rn1a_n = a_1 \cdot r^{n-1}

Where:

  • ana_n is the nn-th term,
  • a1a_1 is the first term,
  • rr is the common ratio,
  • nn is the term number.

For the 7th term, we have:

a7=a1r71=a1r6a_7 = a_1 \cdot r^{7-1} = a_1 \cdot r^6

Substitute the known values:

6=a1(13)66 = a_1 \cdot \left(\frac{1}{3}\right)^6

Simplify (13)6\left(\frac{1}{3}\right)^6:

(13)6=1729\left(\frac{1}{3}\right)^6 = \frac{1}{729}

So, the equation becomes:

6=a117296 = a_1 \cdot \frac{1}{729}

To solve for a1a_1:

a1=6729=4374a_1 = 6 \cdot 729 = 4374

Thus, the first term a1a_1 is 43744374.

Part (b): Finding the exact value of the 15th term of the sequence

Using the same formula for the nn-th term:

a15=a1r151=a1r14a_{15} = a_1 \cdot r^{15-1} = a_1 \cdot r^{14}

Substitute the known values:

a15=4374(13)14a_{15} = 4374 \cdot \left(\frac{1}{3}\right)^{14}

Simplifying (13)14\left(\frac{1}{3}\right)^{14}:

(13)14=14782969\left(\frac{1}{3}\right)^{14} = \frac{1}{4782969}

Thus:

a15=437414782969=43744782969a_{15} = 4374 \cdot \frac{1}{4782969} = \frac{4374}{4782969}

Simplifying this fraction:

a15=22187a_{15} = \frac{2}{2187}

Part (c): Finding the exact value of the sum of the first 10 terms

The formula for the sum of the first nn terms of a geometric sequence is:

Sn=a11rn1rS_n = a_1 \cdot \frac{1 - r^n}{1 - r}

For the first 10 terms:

S10=43741(13)10113=4374115904923S_{10} = 4374 \cdot \frac{1 - \left(\frac{1}{3}\right)^{10}}{1 - \frac{1}{3}} = 4374 \cdot \frac{1 - \frac{1}{59049}}{\frac{2}{3}}

Simplifying:

S10=4374590485904923=4374325904859049S_{10} = 4374 \cdot \frac{\frac{59048}{59049}}{\frac{2}{3}} = 4374 \cdot \frac{3}{2} \cdot \frac{59048}{59049}

S10=656159048590496561S_{10} = 6561 \cdot \frac{59048}{59049} \approx 6561

Thus, the sum of the first 10 terms is approximately 65616561.


Would you like a deeper explanation of any part, or do you have questions?

Here are some related questions to consider:

  1. How would you calculate the sum of infinite terms of this geometric sequence?
  2. What is the value of the common ratio in percentage form?
  3. How does changing the common ratio affect the sequence?
  4. Can you derive the formula for the sum of the first nn terms from the term formula?
  5. How would the 20th term be calculated in this sequence?

Tip: When working with geometric sequences, recognizing the patterns in powers of the common ratio simplifies your calculations.

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Math Problem Analysis

Mathematical Concepts

Geometric Sequences
Exponents
Summation of Series

Formulas

nth term of a geometric sequence: a_n = a_1 * r^(n-1)
Sum of the first n terms of a geometric sequence: S_n = a_1 * (1 - r^n) / (1 - r)

Theorems

Geometric Series Theorem

Suitable Grade Level

Grades 10-12