Math Problem Statement

Function Evaluation, Rule of 4 On the right are four functions, each using one of the function representations we've learned in this lesson. Use functions,
f ( x ) ,

g ( x ) ,

h ( x )

and

p ( t ) to answer the questions on the left. Evaluate
f ( − 5 )

f ( − 5 )

Determine
x when
f ( x )

− 3

x

Evaluate
g ( − 10 )

g ( − 10 )

Determine
x when
g ( x )

− 15

x

Evaluate
h ( 1 )

h ( 1 )

Determine
x when
h ( x )

30

x

Evaluate
p ( 101 )

p ( 101 )

Determine
t when
p ( t )

44

t

f ( x )

1 2 3 4 5 -1 -2 -3 -4 -5 1 2 3 4 5 -1 -2 -3 -4 -5 x y

g ( x ) : {(-16,27), (-15,-4), (-11,6), (-10,-14), (10,43), (50,75), (51,68), (65,17), (72,-15), (74,-10)}

t 20 26 28 44 49 62 82 101 105 111 p ( t ) 32 45 101 99 36 25 44 85 74 41

h ( x )

− 3 x + 15

Solution

To solve the problem, let's go step by step using the functions provided.

Function f(x)f(x)

The representation of this function is a table of values where the xx values are listed along with their corresponding f(x)f(x) values. We will use the provided table for the following evaluations:

1. Evaluate f(5)f(-5):

From the table (assuming you have a table for f(x)f(x)), find the corresponding value of f(5)f(-5).

2. Determine xx when f(x)=3f(x) = -3:

Look for the value of xx in the table where f(x)=3f(x) = -3.

Function g(x)g(x)

The function g(x)g(x) is given by a set of ordered pairs: g(x):{(16,27),(15,4),(11,6),(10,14),(10,43),(50,75),(51,68),(65,17),(72,15),(74,10)}g(x): \{(-16, 27), (-15, -4), (-11, 6), (-10, -14), (10, 43), (50, 75), (51, 68), (65, 17), (72, -15), (74, -10)\}

3. Evaluate g(10)g(-10):

From the given set of ordered pairs, find the value of g(10)g(-10). We see that g(10)=14g(-10) = -14.

4. Determine xx when g(x)=15g(x) = -15:

From the ordered pairs, we see that when g(x)=15g(x) = -15, x=72x = 72.

Function h(x)h(x)

The function is given as: h(x)=3x+15h(x) = -3x + 15

5. Evaluate h(1)h(1):

Substitute x=1x = 1 into the function h(x)h(x): h(1)=3(1)+15=3+15=12h(1) = -3(1) + 15 = -3 + 15 = 12

6. Determine xx when h(x)=30h(x) = 30:

Set h(x)=30h(x) = 30 and solve for xx: 30=3x+1530 = -3x + 15 3015=3x30 - 15 = -3x 15=3x15 = -3x x=5x = -5

Function p(t)p(t)

The function p(t)p(t) is provided as a table with values for tt and their corresponding p(t)p(t).

7. Evaluate p(101)p(101):

From the table, when t=101t = 101, we have p(101)=85p(101) = 85.

8. Determine tt when p(t)=44p(t) = 44:

From the table, we see that p(t)=44p(t) = 44 when t=82t = 82.


Summary of Results:

  1. f(5)f(-5) = (from table).
  2. xx when f(x)=3f(x) = -3 = (from table).
  3. g(10)=14g(-10) = -14.
  4. x=72x = 72 when g(x)=15g(x) = -15.
  5. h(1)=12h(1) = 12.
  6. x=5x = -5 when h(x)=30h(x) = 30.
  7. p(101)=85p(101) = 85.
  8. t=82t = 82 when p(t)=44p(t) = 44.

Would you like further explanations on any of these steps?

Related Questions:

  1. How do you solve for xx in linear equations like h(x)h(x)?
  2. Can you plot the points for g(x)g(x) and p(t)p(t)?
  3. What would happen to h(x)h(x) if the slope changed?
  4. How does interpreting function tables help in real-world situations?
  5. Can you convert function g(x)g(x) into a graph and analyze it?

Tip:

For function evaluations from tables, always ensure the table is read correctly by matching the input value directly with its corresponding output value.

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Math Problem Analysis

Mathematical Concepts

Function Evaluation
Linear Equations
Coordinate Points

Formulas

h(x) = -3x + 15

Theorems

Linear Function Evaluation

Suitable Grade Level

Grades 8-10