Math Problem Statement

If f(x) = √x and g(x) = x^2 + 4, then f(g(x)) is equivalent to:

Solution

The problem is asking for f(g(x))f(g(x)), where:

  • f(x)=xf(x) = \sqrt{x}
  • g(x)=x2+4g(x) = x^2 + 4

Step-by-step solution:

  1. Substitute g(x)g(x) into f(x)f(x): f(g(x))=f(x2+4)f(g(x)) = f(x^2 + 4) Since f(x)=xf(x) = \sqrt{x}, replace the input in ff with g(x)=x2+4g(x) = x^2 + 4:

    f(g(x))=x2+4f(g(x)) = \sqrt{x^2 + 4}

Conclusion:

The correct answer is x2+4\sqrt{x^2 + 4}, which matches the fourth option: x2+4\boxed{\sqrt{x^2 + 4}}

Would you like more details on any specific step?

Here are five related questions to further your understanding:

  1. What is the composition of functions and how is it applied here?
  2. How does the domain of f(g(x))f(g(x)) change based on the functions f(x)f(x) and g(x)g(x)?
  3. What happens if we reverse the functions, i.e., compute g(f(x))g(f(x))?
  4. Can the expression x2+4\sqrt{x^2 + 4} be simplified further?
  5. How would the result change if the function g(x)g(x) were different, e.g., g(x)=x24g(x) = x^2 - 4?

Tip: When composing functions, always ensure you're substituting the entire function, not just part of it.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Square Root Function
Quadratic Function

Formulas

f(g(x)) = f(x^2 + 4) = √(x^2 + 4)

Theorems

Function Composition Theorem

Suitable Grade Level

Grades 9-11