Isaiah brought two dozen donuts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry frosting with cream filling, and the rest had chocolate frosting with sprinkles. What fraction of the donuts had sprinkles? There are 12 donuts in a dozen.


To solve this problem, let's start by calculating the total number of donuts Isaiah brought:

- Isaiah brought **two dozen** donuts.
- Since one dozen equals 12, two dozen is:
  \[
  2 \times 12 = 24 \text{ donuts}
  \]

Next, we determine how many donuts had sprinkles:

1. **Half of the donuts had vanilla frosting with sprinkles**:
   \[
   \frac{1}{2} \times 24 = 12 \text{ donuts}
   \]

2. **2 donuts had strawberry frosting with cream filling**:
   \[
   2 \text{ donuts}
   \]

3. The rest had chocolate frosting with sprinkles. Let's calculate how many that is:

   - First, find out how many donuts have already been accounted for:
     \[
     12 \text{ (vanilla with sprinkles)} + 2 \text{ (strawberry with cream filling)} = 14 \text{ donuts}
     \]
   
   - Subtract this from the total number of donuts to find the remaining donuts (chocolate with sprinkles):
     \[
     24 - 14 = 10 \text{ donuts}
     \]

Now, we add the donuts that have sprinkles (vanilla with sprinkles + chocolate with sprinkles):
\[
12 \text{ (vanilla with sprinkles)} + 10 \text{ (chocolate with sprinkles)} = 22 \text{ donuts with sprinkles}
\]

Finally, to find the fraction of donuts that had sprinkles, we use the total number of donuts:

\[
\frac{22 \text{ donuts with sprinkles}}{24 \text{ total donuts}} = \frac{22}{24}
\]

We can simplify this fraction by dividing the numerator and the denominator by their greatest common divisor, which is 2:

\[
\frac{22 \div 2}{24 \div 2} = \frac{11}{12}
\]

**Therefore, \(\frac{11}{12}\) of the donuts had sprinkles.**

Would you like more details or have any questions?

Here are some related questions:

1. What fraction of the donuts had cream filling?
2. If Isaiah brought 36 donuts instead of 24, how many would have sprinkles?
3. What percentage of the donuts had chocolate frosting with sprinkles?
4. If 3 donuts were taken away from each type, how many would be left with sprinkles?
5. How many donuts would Isaiah need to bring to have an even number of each type?

**Tip:** When dealing with fractions, always look to simplify by finding the greatest common divisor of the numerator and the denominator.

Isaiah brought two dozen donuts to a class party. Half of the donuts had vanilla frosting with sprinkles, 2 had strawberry frosting with cream filling, and the rest had chocolate frosting with sprinkles. What fraction of the donuts had sprinkles? There are 12 donuts in a dozen.

Solve a real-world math problem where Isaiah brings two dozen donuts to a party. Find out what fraction of the donuts had sprinkles using basic arithmetic and fractions. Ideal for students in Grades 4-6.

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