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The problem you're working on is asking how many \( \frac{1}{4} \)-pound hamburgers can be made from 9 \( \frac{1}{6} \) pounds of ground beef.

### Steps:
1. Convert the mixed number \( 9 \frac{1}{6} \) to an improper fraction:
   \[
   9 \frac{1}{6} = \frac{55}{6}
   \]
2. Since each burger weighs \( \frac{1}{4} \) pounds, divide the total amount of beef by \( \frac{1}{4} \). This is equivalent to multiplying by the reciprocal of \( \frac{1}{4} \):
   \[
   \frac{55}{6} \div \frac{1}{4} = \frac{55}{6} \times 4 = \frac{220}{6}
   \]
3. Simplify the fraction \( \frac{220}{6} \):
   \[
   \frac{220}{6} = \frac{110}{3} = 36 \frac{2}{3}
   \]

So, Hannah can make **36 \( \frac{2}{3} \)** hamburgers, which corresponds to the last answer option.

Would you like further details or clarifications?

Here are some related questions:
1. How do you convert a mixed number to an improper fraction?
2. What is the process for dividing fractions?
3. How can you simplify the result \( \frac{220}{6} \)?
4. What is the reciprocal of a fraction, and how is it used in division?
5. Can you express \( 36 \frac{2}{3} \) as a decimal?

**Tip:** Always simplify the fraction as much as possible to get the cleanest result in fraction problems.

Hannah bought 9 1/6 pounds of ground beef to make hamburgers for a party. How many 1/4-pound burgers can she make?

Find out how many 1/4-pound hamburgers Hannah can make from 9 1/6 pounds of ground beef. This problem demonstrates fraction division, mixed numbers, and improper fractions with a detailed step-by-step solution. Ideal for Grades 5-6 students.

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