Math Problem Statement
using I=u∫vdx−u′∫2vdx+u′′∫3vdx what is fourier series of f(x) = |cos x|
Solution
To find the Fourier series of using integration by parts, we'll need to compute the Fourier coefficients. The expression provided,
is a generalized integration by parts formula, but for the Fourier series, we focus on computing the series as follows.
Fourier Series Overview
The Fourier series of a function over is given by:
Where:
Step 1: Symmetry of
Since is an even function, all the sine terms will vanish. Thus, we only need to compute the cosine coefficients and .
Step 2: Compute
The constant term is given by:
Given the symmetry, we can simplify this to:
This integral is straightforward:
Thus,
Step 3: Compute
For (where ), we compute:
Given the symmetry of , we can split this into two intervals as before:
Using trigonometric identities and solving these integrals yields:
Thus, is non-zero only for even , and the Fourier series becomes:
This is the Fourier series for .
Would you like more details or clarifications on any of these steps?
Here are some related questions to explore further:
- What are the differences between odd and even Fourier series?
- How would you calculate the Fourier series for ?
- What is the physical interpretation of the Fourier series coefficients?
- Can the Fourier series be used to approximate non-periodic functions?
- How do complex Fourier series differ from the real Fourier series?
Tip: When computing Fourier coefficients, always check the symmetry of the function (even/odd) to simplify the integrals.
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Math Problem Analysis
Mathematical Concepts
Fourier Series
Even and Odd Functions
Integration by Parts
Trigonometric Integrals
Formulas
Fourier series: f(x) = a_0/2 + Σ (a_n cos(nx) + b_n sin(nx))
a_n = (1/π) ∫[−π to π] f(x) cos(nx) dx
b_n = (1/π) ∫[−π to π] f(x) sin(nx) dx
a_0 = (1/π) ∫[−π to π] f(x) dx
Integration by parts formula: I = u ∫ vdx − u′ ∫ vdx + u′′ ∫ vdx
Theorems
Fourier Series Theorem
Even Function Theorem
Suitable Grade Level
Undergraduate