Math Problem Statement

  1. How many four digit numbers can be formed using the digits 4,5,6,9 without repeating any of the digits? How many of these numbers lie between 4000 and 6000?

Solution

Let's break this problem down step by step.

Part 1: Total number of four-digit numbers

We need to form four-digit numbers using the digits 4, 5, 6, and 9, with no repetition of any digits.

  • Step 1: The first digit must be chosen from the available digits 4, 5, 6, or 9. So, there are 4 choices for the first digit.
  • Step 2: After choosing the first digit, there are 3 remaining choices for the second digit.
  • Step 3: For the third digit, after two digits are chosen, there are 2 remaining choices.
  • Step 4: For the fourth digit, after three digits are chosen, there is 1 remaining choice.

Thus, the total number of four-digit numbers that can be formed without repetition is:

4×3×2×1=244 \times 3 \times 2 \times 1 = 24

Part 2: Four-digit numbers between 4000 and 6000

To ensure the number is between 4000 and 6000, the first digit must be 4 or 5. Let's break it down:

  • Step 1: If the first digit is 4, then the remaining digits (5, 6, and 9) can be arranged in any order for the other three positions. There are 3 choices for the second digit, 2 choices for the third, and 1 choice for the fourth. So, there are:

    3×2×1=63 \times 2 \times 1 = 6

  • Step 2: If the first digit is 5, then the remaining digits (4, 6, and 9) can also be arranged in any order for the other three positions. Again, there are:

    3×2×1=63 \times 2 \times 1 = 6

Thus, the total number of numbers between 4000 and 6000 is:

6+6=126 + 6 = 12

Final Answer:

  • The total number of four-digit numbers that can be formed using the digits 4, 5, 6, 9 without repetition is 24.
  • The total number of such numbers between 4000 and 6000 is 12.

Do you want any additional explanations or further details on these calculations?

Here are five related questions you might find interesting:

  1. How many four-digit numbers can be formed using any 4 digits from 0 to 9, without repetition?
  2. What is the probability that a randomly chosen four-digit number from the above set is between 4000 and 6000?
  3. If the digits could repeat, how many four-digit numbers can be formed?
  4. What if the first digit had to be a number between 1 and 5, how many numbers could be formed?
  5. How would the number of valid four-digit numbers change if the digits 4, 5, 6, and 9 were used but there was no restriction on the first digit?

Tip: When you're dealing with such problems, always consider constraints on the first digit first, as it often narrows down your choices significantly.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Permutations
Counting Principle

Formulas

n! = n × (n-1) × (n-2) × ... × 1 (for permutations)

Theorems

Fundamental Counting Principle

Suitable Grade Level

Grades 7-9