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The problem asks to determine how many distinct three-digit numbers can be formed using the digits 4, 5, 6, 7, 8, and 9, where the resulting number is less than 900, and no digits are repeated.

### Step-by-step approach:

1. **Hundreds place**: 
   The number must be less than 900, so the digit in the hundreds place must be either 4, 5, 6, 7, or 8 (since 9 would make the number greater than or equal to 900). Thus, there are 5 choices for the hundreds place.

2. **Tens

Dari angka 4, 5, 6, 7, 8, dan 9 akan disusun bilangan ratusan dengan angka-angka berbeda. Banyaknya bilangan ratusan yang dapat disusun dan kurang dari 900 adalah ... bilangan.

Learn how to determine the number of distinct three-digit numbers that can be formed using digits 4, 5, 6, 7, 8, and 9, where the result is less than 900. This problem covers key concepts in combinatorics and permutations. Suitable for students in Grades 8-10.

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