Math Problem Statement

löse mir die aufgabe 9 mit den koordinaten: H(1/2/2), E(3/2/2), F(3/6/2), G(1/6/2), C(1/6/-1), D(1/2/-1), A(3/2/-1), B(3/6/-1), H(1/2/2).

Solve problem 9 using the coordinates: H(1/2/2), E(3/2/2), F(3/6/2), G(1/6/2), C(1/6/-1), D(1/2/-1), A(3/2/-1), B(3/6/-1), H(1/2/2).

Solution

To solve task 9, we are asked to determine the coordinates of the points M1,M2,M3,M4M_1, M_2, M_3, M_4, which are the intersection points of the diagonals of various planes in the cuboid, as well as the coordinates of the vectors M1M2,M2M3,M3M4,M4M1\overrightarrow{M_1M_2}, \overrightarrow{M_2M_3}, \overrightarrow{M_3M_4}, \overrightarrow{M_4M_1}.

Step 1: Coordinates of M1,M2,M3,M4M_1, M_2, M_3, M_4

We will find the coordinates of each MiM_i by determining the midpoints of the diagonals in the specified planes.

  • M1M_1: Midpoint of the diagonal of rectangle ABCDABCD = \left( \frac{3+1}{2}, \frac{2+6}{2}, \frac{-1 + (-1)}{2} \right) = (2, 4, -1)$$
  • M2M_2: Midpoint of the diagonal of rectangle BCGFBCGF = \left( \frac{3+1}{2}, \frac{6+6}{2}, \frac{-1+2}{2} \right) = (2, 6, 0.5)$$
  • M3M_3: Midpoint of the diagonal of rectangle CDHGCDHG = \left( \frac{1+1}{2}, \frac{6+2}{2}, \frac{-1+2}{2} \right) = (1, 4, 0.5)$$
  • M4M_4: Midpoint of the diagonal of rectangle ADHEADHE = \left( \frac{3+3}{2}, \frac{2+2}{2}, \frac{-1+2}{2} \right) = (3, 2, 0.5)$$

Step 2: Coordinates of the Vectors

Now, we find the coordinates of the vectors by subtracting the coordinates of the points involved.

  • M1M2\overrightarrow{M_1M_2} M1M2=M2M1=(2,6,0.5)(2,4,1)=(0,2,1.5)\overrightarrow{M_1M_2} = M_2 - M_1 = (2, 6, 0.5) - (2, 4, -1) = (0, 2, 1.5)

  • M2M3\overrightarrow{M_2M_3} M2M3=M3M2=(1,4,0.5)(2,6,0.5)=(1,2,0)\overrightarrow{M_2M_3} = M_3 - M_2 = (1, 4, 0.5) - (2, 6, 0.5) = (-1, -2, 0)

  • M3M4\overrightarrow{M_3M_4} M3M4=M4M3=(3,2,0.5)(1,4,0.5)=(2,2,0)\overrightarrow{M_3M_4} = M_4 - M_3 = (3, 2, 0.5) - (1, 4, 0.5) = (2, -2, 0)

  • M4M1\overrightarrow{M_4M_1} M4M1=M1M4=(2,4,1)(3,2,0.5)=(1,2,1.5)\overrightarrow{M_4M_1} = M_1 - M_4 = (2, 4, -1) - (3, 2, 0.5) = (-1, 2, -1.5)

Summary:

  • Coordinates of M1=(2,4,1)M_1 = (2, 4, -1)

  • Coordinates of M2=(2,6,0.5)M_2 = (2, 6, 0.5)

  • Coordinates of M3=(1,4,0.5)M_3 = (1, 4, 0.5)

  • Coordinates of M4=(3,2,0.5)M_4 = (3, 2, 0.5)

  • Vector M1M2=(0,2,1.5)\overrightarrow{M_1M_2} = (0, 2, 1.5)

  • Vector M2M3=(1,2,0)\overrightarrow{M_2M_3} = (-1, -2, 0)

  • Vector M3M4=(2,2,0)\overrightarrow{M_3M_4} = (2, -2, 0)

  • Vector M4M1=(1,2,1.5)\overrightarrow{M_4M_1} = (-1, 2, -1.5)

Do you have any further questions or need clarification?

Related Questions:

  1. How do you find the midpoint of a diagonal in a 3D space?
  2. How do you calculate the vector between two points in 3D?
  3. What is the significance of diagonal midpoints in a cuboid?
  4. Can you explain the vector subtraction method for any two points?
  5. How would you calculate the distance between two midpoints?

Tip:

When calculating vectors between points, always subtract coordinates in the same order (final minus initial) to ensure the correct direction.

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Math Problem Analysis

Mathematical Concepts

3D Geometry
Vector Calculation
Midpoint Formula

Formulas

Midpoint formula: M = ((x1+x2)/2, (y1+y2)/2, (z1+z2)/2)
Vector formula: Vector AB = B - A

Theorems

Midpoint Theorem
Vector Subtraction

Suitable Grade Level

Grades 10-12