Math Problem Statement

Find m∠EFC given that m∠DCF = 110° and BD and EG are parallel lines.

Solution

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The problem states that BDBD and EGEG are parallel lines, and you are tasked with finding mEFCm\angle EFC given that mDCF=110m\angle DCF = 110^\circ.


Solution:

Step 1: Recognize the relationship between the angles

From the diagram:

  • DCF\angle DCF and EFC\angle EFC are supplementary because they are adjacent angles forming a straight line (linear pair).

Step 2: Apply the supplementary angle rule

Angles forming a straight line always add up to 180180^\circ. Thus: mDCF+mEFC=180m\angle DCF + m\angle EFC = 180^\circ

Step 3: Solve for mEFCm\angle EFC

110+mEFC=180110^\circ + m\angle EFC = 180^\circ mEFC=180110m\angle EFC = 180^\circ - 110^\circ mEFC=70m\angle EFC = 70^\circ


Final Answer:

mEFC=70m\angle EFC = 70^\circ

Would you like an explanation of parallel line angle properties or any additional help?


Related Questions:

  1. How do we use alternate interior angles to identify relationships in parallel lines?
  2. What is the significance of corresponding angles in this setup?
  3. If mDCF=110m\angle DCF = 110^\circ, what is mHFEm\angle HFE in the diagram?
  4. Can you identify another pair of supplementary angles in this figure?
  5. What would happen to these relationships if the lines were not parallel?

Tip: When working with parallel lines and transversals, always look for alternate interior, corresponding, and supplementary angles to simplify the solution process!

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Math Problem Analysis

Mathematical Concepts

Supplementary Angles
Parallel Lines
Linear Pairs

Formulas

m∠DCF + m∠EFC = 180°

Theorems

Supplementary Angles Theorem

Suitable Grade Level

Grades 7-9